Question

#include

Answer 1

Answer:

a.No output is printed on the screen

Explanation:

As is the function an error will be printed because fork() is not declared in the scope, to define an output we need to see the full content of the code; because 'value' is an integer the 'printf' function is not well defined and the library for execlp is not defined; in general, this code will throw multiple errors in execution.