The magnitude of each vector is the Pythagorean sum of its components.
a. |v1| = √(2² + (-6)²) = √40 = 2√10
|v2| = √((-4)² + 7²) = √65
b. To make each vector into a unit vector, divide each component by the vector's magnitude.
u1 = v1/|v1| = (2/(2√10), -6/(2√10))
u1 = (√10/10, -3√10/10)
u2 = v2/|v2| = (-4/√65, 7/√65)
u2 = (-4√65/65, 7√65/65)
Answer: 0
First: Move constant to the left by adding its opposite to both sides
-3x+2y-7=7-7
Then: Change the signs on both sides of the equation
3x-2y+7
Equaling: 3x-2y+7=0
Answer:
none of the answer above
the answer is X < -1/4
Step-by-step explanation:
7x-3x<1-2
4x<-1
x<-1/4
Take your original equation 
and multiply both sides by 
to remove the fractions. You are left with
So,
Update: There is no numerical answer that can be found without being given a value for either x or y
Answer:
9x^2 - 10x -4
Step-by-step explanation:
It is set up like this
9x^2 - 8x
- (x-2)2
First solve (x-2)2
the answer is (2x-4)
so now you can do this instead
9x^2 - 8x
- 2x - 4
----------------------------------
9x^2 - 10x +4
9x^2 minus zero is 9x^2
-8x-2x is -10x
0- -4 is 4 because that is like saying 0 + 4 because double negatives equal a positive
A simpler way is to change all the numbers to the opposite sign and then change the minus to a plus
like this
9x^2 - 8x
+ -2x + 4
----------------------------------
9x^2 - 10x +4
