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Brums [2.3K]
3 years ago
8

After eliminating radicals, what quadratic equation can you solve to find the potential solutions of ..

Mathematics
1 answer:
sasho [114]3 years ago
4 0

Answer:

Step-by-step explanation:

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What is the median of the following numbers 45,36,52,55,47, 39
Elena L [17]

Answer:

46

Step-by-step explanation:

By arranging the numbers from least to greatest, you can find the median by locating the central number in the data set.

8 0
3 years ago
Help please!!<br> Solve for X.
Mekhanik [1.2K]

9514 1404 393

Answer:

  3) x = 9

  4) x = 3

Step-by-step explanation:

3) The two short segments are indicated as having a sum equal to the long segment.

  (x +2) +(-5 +x) = 15

  2x = 18 . . . . . . . . . . . . add 3

  x = 9 . . . . . . . . . divide by 2

(This makes the segments be 9+2 = 11 and -5+9 = 4, which total 15.)

__

4) Same deal.

  3x +3 = 4x

  3 = x . . . . . . . . subtract 3x

(This makes the segments be 3(3) = 9 and 4(3) = 12, where 9+3=12.)

6 0
3 years ago
Graph this function:<br> y - 5 = -3(x + 3)<br> Click to select points on the graph.
makvit [3.9K]
Root: (-4/3, 0)
vertical intercept: (0, -4)

6 0
3 years ago
Read 2 more answers
Assume that the total revenue received from the sale of x items is given​ by, ​R(x)equals34 ln (4 x plus 5 )​, while the total c
katen-ka-za [31]

Answer:

63 units

Step-by-step explanation:

The profit function P(x) is given by the revenue function minus the cost function:

P(x) = R(x) - C(x)\\P(x) = 34ln(x+5)-\frac{x}{2}

The number of units sold 'x' for which the derivate of the profit function is zero, is the number of units that maximizes profit:

P(x) = 34ln(x+5)-\frac{x}{2}\\P'(x) =0= \frac{34}{x+5}-\frac{1}{2}\\x+5=68\\x=63\ units

The number of units that should be manufactured so that​ profit is maximum is 63 units.

5 0
3 years ago
Can someone help pls?!?!?
Reil [10]

to factor it the answer is (x+1)(x+1)

to simplify it the answer is x2+2x+1

idk if this helped or not but here you go

8 0
3 years ago
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