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SpyIntel [72]
3 years ago
14

OB is the bisector of AD and EC. . EO = 2x – 20 and OC = 70 – x. Solve for x.

Mathematics
1 answer:
mixas84 [53]3 years ago
4 0
<span>We know that OB bisects EC where they intersect would be at point O, 
so the two lengths EO and OC must be equal. 

2x - 20 = 70 - x 

</span>[adding x + 20 to each side] 

2x - 20 + x + 20 = 70 - x + x + 20

[simplifying]

<span>3x = 90 

</span>[dividing each side by 3]
<span>
x = 30 would be the answer</span>
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Find two complex numbers that have a sum of i10 a different of -4and a product of -29​
lianna [129]
<h2>-2+5i and 2+5i</h2>

Step-by-step explanation:

   Let the complex numbers be a+ib\textrm{ and }c+id.

Given, sum is 10i, difference is -4 and product is -29.

(a+c)+i(b+d)=10i ⇒ a+c=0,b+d=10

(a-c)+i(b-d)=-4 ⇒ a-c=-4,b-d=0

a=-2,c=2,b=5,d=5

(a+ib)(c+id)=(-2+5i)(2+5i)=-4-25=-29

Hence, all three equations are consistent yielding the complex numbers -2+5i\textrm{ and }2+5i.

8 0
2 years ago
A square and a rectangle have equal area.The rectangle is 64 cm by 81 cm. What is the perimeter of the square?
Fittoniya [83]

Answer:

2592 cm

Step-by-step explanation:

square area = x²

rectangle area = bh

so

x² = bh

since the areas are equal

b and h are in the problem as 64 and 81

x² = 64x81

x² = 5184

divide by 2

x = 2592 cm

6 0
3 years ago
Find the length of the missing side.<br> Please help!
BigorU [14]

Answer:

15

Step-by-step explanation:

a2+b2=c2

4 0
3 years ago
an amount of 17,000 is borrowed for 14 years at 9% interest, compounded annually. If the loan is paid in full at the end of that
Marta_Voda [28]

Step-by-step explanation:

56809.35946 must be paid back

8 0
3 years ago
X+6y=27<br> 7x-3y=9 por metodo de igualacion
GalinKa [24]

Answer:

(3,4)

Step-by-step explanation:

The system of equations is:

x+6y=27

7x-3y=9.

I looked up "metodo de igualacion". It is basically American for doing substitution.

However, the only difference is you are asked to solve both equations for a variable.

The first equation looks easy to solve for x. So I'm going to solve both equations for x.

x+6y=27

Subtract 6y on both sides:

x     =-6y+27

7x-3y=9

Add 3y on both sides:

7x    =3y+9

Divide both sides by 7:

x     =3/7 y +9/7

So both equations are solved for x.  You want to find when the x's are the same because you are looking for a common amongst the lines given.

So we have

-6y+27=3/7 y  +9/7

I hate the fractions honestly so I'm going to multiply both sides by 7 so they will no longer be for now:

-42y+189=3y + 9

Now add 42y on both sides:

         189=45y+9

Subtract 9 on both sides:

        180=45y

Divide both sides by 45:

            4=y

If 4=y, then y=4.

So now once we have obtain 4 for y, we will use one of the equations given along with it to find x. Just choose one. Choose the easier looking one to you.

I like the x=-6y+27 with y=4.

So replace y with giving you:

x=-6(4)+27

x=-24+27

x=3

So the solution is (x,y)=(3,4).

x=3 and y=4.

8 0
3 years ago
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