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3 years ago

7

Eight minus the quotient of two and a number x

2 answers:

algol [13]3 years ago

8 0

8-2/x ---------------------------------

frosja888 [35]3 years ago

7 0

<span> Eight minus the quotient of two and a number x =</span> 8-2÷X

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When records were first kept (t=0), the population of a rural town was 260 people. During the following years, the population gr

Firdavs [7]

Answer:

(a) The population after 15 years is 2678.

(b)Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

Step-by-step explanation:

Given that,

The population grew at a rate of

$P'(t)=45(1+\sqrt t)$

Integrating both sides

$\int P'(t) dt=\int 45(1+\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int (45+45\sqrt t)dt$

$\Rightarrow \int P'(t) dt=\int 45\ dt+\int 45\sqrt t\ dt$

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac12+1}}{\frac12+1}+c$ [ c is integration constant]

$\Rightarrow P(t)= 45t+45\ \frac{t^{\frac32}}{\frac32}+c$

$\Rightarrow P(t)= 45t+45\times\frac 23 \times {t^{\frac32}}+c$

$\Rightarrow P(t)= 45t+30 {t^{\frac32}}+c$

When t=0 , P(0)= 260

$\therefore 260= 45\times0+30\times {0^{\frac32}}+c$

$\Rightarrow c=260$

$\therefore P(t)= 45t+30 {t^{\frac32}}+260$

Therefore the population P(t) at any time t>0 is

$P(t)= 45t+30 {t^{\frac32}}+260$

To find the population after 15 years, we need to plug t=15 in the above expression.

$P(15)=( 45\times 15)+30( {15^{\frac32}})+260$

≈2678

The population after 15 years is 2678.

5 0

3 years ago

Which equation is equivalent to 4. 5 = 2a? a = 2. 5 a = 2. 25 4. 5a = 2 a 2 = 4. 5.

Art [367]

Answer:

a=2.25

Step-by-step explanation:

Given the equation 4.5=2a, you'd finds the value of "a" and divide both sides by 2.

4.5/2=a

2.25=a

a=2.25

6 0

3 years ago

Answers anybody?????

viva [34]

The area is the same no matter how you calculate it.
.. (1/2)*20*12 = (1/2)*30*h
.. h = (2/3)*12 = 8 . . . . . feet

8 0

3 years ago