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4 years ago

Combine these two sentences using a subordinate conjunction

Mathematics

1 answer:

stellarik [79]4 years ago

8 0

Answer:

Charles wanted to buy a new guitar, so Charles saved his money for three months

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HELP GEOMETRY find x and y

GenaCL600 [577]

A well-known formula gives us that $y = \frac{6x-3x}{2} = \frac{3x}{2}$ . Additionally, the sum of the angles in a circle is 360, so $6x+3x=9x=360$ , so $x=40^\circ$ . Therefore, $y = 60^\circ$ .

8 0

3 years ago

Select the two values of x that are roots of this equation.

charle [14.2K]

Answer:

$x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2}$

Step-by-step explanation:

$x = \frac{ - b + - \sqrt{ {b}^{2} - 4ac} }{2a} \\ = \frac{ - 3 + - \sqrt{9 + 24} }{2} \\ x1 = \frac{ - 3 - \sqrt{33} }{2} \\ x2 = \frac{ - 3 + \sqrt{33} }{2}$

7 0

3 years ago

How many different situations arise when five coins are thrown into the air?

svet-max [94.6K]

Each coin will either land as a head or a tail. - 2 possible results.
for 5 coins its 2*2*2*2*2 = 32 different results.

4 0

3 years ago

A dish washer manufacturer introduced a new type of dish washer and conducted a survey on the new product. The survey showed 40%

antoniya [11.8K]

Answer:

$P(A \cup B) =0.45$

Step-by-step explanation:

From the question we are told that

Consumers seen the soap $P_A=40\% =0.40$

Consumers used the soap $P_B=20\% =0.2$

Consumers seen/tried the soap $P_x=15\% =0.15$

Generally the probability that consumers have seen and tried the soap is

$P(A \cup B=P(A)+P(B)-P(A \cap B$

$P(A \cup B=0.4+0.2-0.15$

$P(A \cup B) =0.45$

7 0

3 years ago

The blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of

Effectus [21]

Answer:

(a) Approximately 68 % of women in this group have platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7.

(b) Approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

Step-by-step explanation:

We are given that the blood platelet counts of a group of women have a bell-shaped distribution with a mean of 257.62 and a standard deviation of 62.1

Let X = <u><em>the blood platelet counts of a group of women</em></u>

So, X ~ Normal( $\mu=257.62, \sigma^{2} =62.1^{2}$ )

Now, the empirical rule states that;

68% of the data values lie within the 1 standard deviation of the mean.

95% of the data values lie within the 2 standard deviations of the mean.

99.7% of the data values lie within the 3 standard deviations of the mean.

(a) The approximate percentage of women with platelet counts within 1 standard deviation of the mean, or between 195.5 and 319.7 is 68% according to the empirical rule.

(b) The approximate percentage of women with platelet counts between 71.3 and 443.9 is given by;

z-score of 443.9 = $\frac{X-\mu}{\sigma}$

= $\frac{443.9-257.62}{62.1}$ = 3

z-score of 71.3 = $\frac{X-\mu}{\sigma}$

= $\frac{71.3-257.62}{62.1}$ = -3

So, approximately 99.7% of women in this group have platelet counts between 71.3 and 443.9.

5 0

3 years ago