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3 years ago

7

The ratio of the longer side of a rectangle to its

1 answer:

Nadusha1986 [10]3 years ago

8 0

Answer:

28 ft

Step-by-step explanation:

Given,

The ratio of the longer side of a rectangle to its shorter side=4:3

It is said that the length of the shorter side is 21 ft.

Let the longer side be x.

Then,

4:3=x:21

or,4/3=x/21

or,x=(4*21)/3=28 ft. [ANS]

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What's the answer to 1.6(2.5-10)+8.2=???

V125BC [204]

Answer:

-3.8

Step-by-step explanation:

1.6(2.5-10) + 8.2

1.6(-7.5) + 8.2

-12 + 8.2

-3.8

5 0

3 years ago

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I need help with this math problem

vivado [14]

A cannot be the answer.
The maximum distance he can travel is 420 miles. He has gone 180. He still has 420 - 180 = 240 miles left to go.

C The distance is correct in the first set of brackets, but you cannot add distance divided by time (which is a speed) to distance.

D is incorrect. The first set of brackets is correct, but the second set is meaningless. Distances and rates do not mix.

B <<<<< Answer If you divide the remaining distance (240) by the rate (180/3) you get the correct answer of 4 hours.

B <<<< answer.

4 0

3 years ago

Match solutions and differential equations. Note: Each equation may have more than one solution. Select all that apply. (a) 7y''

Nonamiya [84]

Answer:

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

Step-by-step explanation:

a.7 y''-7 y =0

Auxillary equation

$D^2-1=0$

$(D-1)(D+1)=0$

D=1,-1

Then , the solution of given differential equation

$y=e^x,y=e^{-x}$

2. $7x^2y''+14xy'-14 y=0$

Y= $y=x^3$

$y=3x^2$

$y''=6x$

Substitute in the given differential equation

$42x^3+42x^3-14x^3\neq 0$

Hence, $x^3$ is not a solution of given differential equation

$e^x,e^{-x}$ are also not a solution of given differential equation.

y= $x^{-2}$

$y'=-2x^{-3}$

$y''=6x^{-4}$

Substitute the values in the differential equation

$7x^2(6x^{-4})+14x(-2x^{-3})-14 x^{-2}$

= $42x^{-2}-28x^{-2}-14x^{-2}=0$

Hence, $x^{-2}$ is a solution of given differential equation.

c. $7x^2y''-42y=0$

$y=x^3$

$y'=3x^2$

$y''=6x$

Substitute the values in the differential equation

$42x^3-42x^3=0$

Hence, $x^3$ is a solution of given differential equation.

a- $e^x,e^{-x}$

b- $x^{-2}$

c- $x^3$

6 0

3 years ago

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Kiki has 1/6 pound of blueberries and 5/8 pound of raspberries.

Darina [25.2K]

Answer: Did this all by myself 1/6 is closer to 0 and 5/8 is closer to 1/2 so the answer is 1/2 0 then 1/2 then 1/3 again

Step-by-step explanation:

1/ 6 -5 /8 =(1 × 4 6 × 4) – (5 × 3 8 × 3) = 4 /24 – 15 /24 = 4 – 15 24 = – 11 24

7 0

3 years ago

Make for me number 21 thx

xz_007 [3.2K]

Method One

You could divide by 5 right away.

20/5 = - 3 + x

4 = - 3 + x Add 3 to both sides.

4 + 3 = x

x = 7

Method Two.

You could remove the brackets. This is slightly longer, but some questions can only be solved that way.

20 = 5(-3) + 5x

20 = -15 + 5x Add 15 to both sides

20 + 15 = 5x

35 = 5x Divide by 5

35/5 = x

7 = x

8 0

3 years ago