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adoni [48]
3 years ago
13

In? gambling, the chances of winning are often written in terms of odds rather than probabilities. The odds of winning is the ra

tio of the number of successful outcomes to the number of unsuccessful outcomes. The odds of losing is the ratio of the number of unsuccessful outcomes to the number of successful outcomes. For? example, if the number of successful outcomes is 2 and the number of unsuccessful outcomes is? 3, the odds of winning are 2:3(Note; if the odds of winning are 2/3, the propability of sucess is2/5)
The odds of event occuring are 1:6. Find (a) the propability that the event will occur,(b) propability that the event will not occur.

(a)The propability that event will occur is....(TYPE AN INTEGER OR DECIMAL ROUNDED TO THE NEAREST THOUSANDTH AS NEEDED.)

(b)The propability thet the event will not occur is...(TYPE AN INTEGER OR DECIMAL ROUNDED TO THE NEAREST THOUSANDTH AS NEEDED)
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
5 0

Answer:

A) The probability that the event will occur=\frac{1}{7}

B)The probability that the event will not occur = \frac{6}{7}

Step-by-step explanation:

We are given that The odds of event occurring are 1:6.

So, Number of successful events = 1

Number of unsuccessful events = 6

So, Total events = 6+1=7

a)the probability that the event will occur=\frac{\text{Favorable event}}{\text{Total event}}

The probability that the event will occur=\frac{1}{7}

b)The probability that the event will not occur =\frac{\text{Favorable event}}{\text{Total event}}

The probability that the event will not occur = \frac{6}{7}

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the derivitive is just the slope

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\qquad\qquad\huge\underline{{\sf Answer}}

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