Answer:
X = 0 or X = -2
Step-by-step explanation:
2x^4 + 16x = 0
x^4 + 8x = 0
x(x+2) (4+x^2_2x) = 0
x + 2 = 0
or
4+x^2_2x=0
Answer:
Option (c) is correct
Step-by-step explanation:
Case (a)
A = 3 + 5i = (3, 5)
B = 2 + 2i = (2, 2)
C = 5i = (0, 5)
Use the distance formula to find the distance between two points
![AB = \sqrt{(2-3)^{2}+(2-5)^{2}}=\sqrt{10}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%282-3%29%5E%7B2%7D%2B%282-5%29%5E%7B2%7D%7D%3D%5Csqrt%7B10%7D)
![BC = \sqrt{(0-2)^{2}+(5-2)^{2}}=\sqrt{13}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%280-2%29%5E%7B2%7D%2B%285-2%29%5E%7B2%7D%7D%3D%5Csqrt%7B13%7D)
![CA = \sqrt{(0-3)^{2}+(5-5)^{2}}=\sqrt{9}](https://tex.z-dn.net/?f=CA%20%3D%20%5Csqrt%7B%280-3%29%5E%7B2%7D%2B%285-5%29%5E%7B2%7D%7D%3D%5Csqrt%7B9%7D)
For the triangle to be right angles triangle
![BC^{2}=AB^{2}+CA^{2}](https://tex.z-dn.net/?f=BC%5E%7B2%7D%3DAB%5E%7B2%7D%2BCA%5E%7B2%7D)
Here, it is not valid, so these are not the points of a right angled triangle.
Case (b)
A = 2i = (0, 2)
B = 3 + 5i = (3, 5)
C = 4 + i = (4, 1)
Use the distance formula to find the distance between two points
![AB = \sqrt{(3-0)^{2}+(5-2)^{2}}=\sqrt{18}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%283-0%29%5E%7B2%7D%2B%285-2%29%5E%7B2%7D%7D%3D%5Csqrt%7B18%7D)
![BC = \sqrt{(4-3)^{2}+(1-5)^{2}}=\sqrt{17}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%284-3%29%5E%7B2%7D%2B%281-5%29%5E%7B2%7D%7D%3D%5Csqrt%7B17%7D)
![CA = \sqrt{(4-0)^{2}+(1-2)^{2}}=\sqrt{17}](https://tex.z-dn.net/?f=CA%20%3D%20%5Csqrt%7B%284-0%29%5E%7B2%7D%2B%281-2%29%5E%7B2%7D%7D%3D%5Csqrt%7B17%7D)
For the triangle to be right angles triangle
![AB^{2}=BC^{2}+CA^{2}](https://tex.z-dn.net/?f=AB%5E%7B2%7D%3DBC%5E%7B2%7D%2BCA%5E%7B2%7D)
Here, it is not valid, so these are not the points of a right angled triangle.
Case (c)
A = 6 + 4i = (6, 4)
B = 7 + 5i = (7, 5)
C = 8 + 4i = (8, 4)
Use the distance formula to find the distance between two points
![AB = \sqrt{(7-6)^{2}+(5-4)^{2}}=\sqrt{2}](https://tex.z-dn.net/?f=AB%20%3D%20%5Csqrt%7B%287-6%29%5E%7B2%7D%2B%285-4%29%5E%7B2%7D%7D%3D%5Csqrt%7B2%7D)
![BC = \sqrt{(8-7)^{2}+(4-5)^{2}}=\sqrt{2}](https://tex.z-dn.net/?f=BC%20%3D%20%5Csqrt%7B%288-7%29%5E%7B2%7D%2B%284-5%29%5E%7B2%7D%7D%3D%5Csqrt%7B2%7D)
![CA = \sqrt{(8-6)^{2}+(4-4)^{2}}=\sqrt{4}](https://tex.z-dn.net/?f=CA%20%3D%20%5Csqrt%7B%288-6%29%5E%7B2%7D%2B%284-4%29%5E%7B2%7D%7D%3D%5Csqrt%7B4%7D)
For the triangle to be right angles triangle
![CA^{2}=BC^{2}+AB^{2}](https://tex.z-dn.net/?f=CA%5E%7B2%7D%3DBC%5E%7B2%7D%2BAB%5E%7B2%7D)
Here, it is valid, so these are the points of a right angled triangle.
What is the relationship between the volume of the sphere and the volume of the cylinder? (Answer: The sphere takes up two-thirds of the volume of the cylinder.) What is the relationship between the volume of the cone and the volume of the cylinder? (Answer: The cone takes up one-third of the volume of the cylinder.)
Answer:
1 foot?
Step-by-step explanation:
You subtract 13 from 12 to get the base divider.
You probably just need to simplify the expression. To do this you just combine like terms. So you would subtract 38 from the 10 to get -28x and then subtract 47 from 36 which gives you -11. Your expression should be -28x-11.<span />