Question 1:
For this case we have to:
h: Let the variable representing the amount of hours Liv was offered.
y: Let the variable representing the number of hours Gavin was offered.
According to the data we have to:
![h + y = 50\\y = h-4](https://tex.z-dn.net/?f=h%20%2B%20y%20%3D%2050%5C%5Cy%20%3D%20h-4)
So, replacing the second equation in the first we have:
![h + (h-4) = 50\\h + h-4 = 50\\2h = 54](https://tex.z-dn.net/?f=h%20%2B%20%28h-4%29%20%3D%2050%5C%5Ch%20%2B%20h-4%20%3D%2050%5C%5C2h%20%3D%2054)
With that equation we find the number of hours of Liv (
) and then we find the number of hours of GAvin (
)
ANswer:
![2h = 54](https://tex.z-dn.net/?f=2h%20%3D%2054)
Question 2:
For this case we have that by definition, the distance traveled is given by:
![x = v * t](https://tex.z-dn.net/?f=x%20%3D%20v%20%2A%20t)
Where:
x: It is the distance traveled
v: It's the speed
t: It's time
According to the data we have to:
![v = s\\t = 0.75](https://tex.z-dn.net/?f=v%20%3D%20s%5C%5Ct%20%3D%200.75)
Substituting we have:
![x = 0.75s](https://tex.z-dn.net/?f=x%20%3D%200.75s)
Answer:
![x = 0.75s](https://tex.z-dn.net/?f=x%20%3D%200.75s)
Question 3:
For this case we have to:
m: Be the variable that represents the number of meters Alexis swam
y: Be the variable that represents the number of meters that Swim sade
According to we have to:
![m+y = 200\\y = \frac {m} {2}](https://tex.z-dn.net/?f=m%2By%20%3D%20200%5C%5Cy%20%3D%20%5Cfrac%20%7Bm%7D%20%7B2%7D)
Substituting the second equation into the first we have:
![m +\frac {m} {2} = 200](https://tex.z-dn.net/?f=m%20%2B%5Cfrac%20%7Bm%7D%20%7B2%7D%20%3D%20200)
Thus, with the previous equation we can find the amount of meters that Alexis swam.
Answer:
![m +\frac {m} {2} = 200](https://tex.z-dn.net/?f=m%20%2B%5Cfrac%20%7Bm%7D%20%7B2%7D%20%3D%20200)
Question 4:
For this case we have to:
g: Let the variable representing the amount of peanuts Grace ate
y: Let the variable representing the amount of peanuts Kenoa ate
According to the data we have to:
![g + y = 40\\y + 5 = g](https://tex.z-dn.net/?f=g%20%2B%20y%20%3D%2040%5C%5Cy%20%2B%205%20%3D%20g)
According to the first equation we have to:
![y = 40-g](https://tex.z-dn.net/?f=y%20%3D%2040-g)
If we substitute in the second equation:
![40-g + 5 = g\\45 = 2g](https://tex.z-dn.net/?f=40-g%20%2B%205%20%3D%20g%5C%5C45%20%3D%202g)
Answer:
![45 = 2g](https://tex.z-dn.net/?f=45%20%3D%202g)