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3 years ago

Area of trapezoids 2in,4in,6in

Mathematics

1 answer:

Sindrei [870]3 years ago

3 0

Answer:

Step-by-step explanation:

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On a number line, the coordinates of A, B, C, and Dare -6, -2, 3, and 7, respectively. Find

den301095 [7]

Answer:

9: not congruent AB=-8 and CD=10

10: not congruent AC=-3 and BD=5

11: congruent BC=1 and AD=1

5 0

3 years ago

A bag contains only black marbles and white marbles . Ezra reached into the bag without looking , got 30 marbles , and found tha

Keith_Richards [23]

2/5

Since 12 out of 30 marbles were black, you can assume that the percentage of black marbles in the bag is 40% (Ex: 12/30=.4) The probability that the marble you pick is black is equal to the percentage of black marbles in the bag. 40% is equal to 2/5.

6 0

3 years ago

Read 2 more answers

The area of a garden is (x^2-x-6) square yards. Find the dimensions of the garden is x=5

kicyunya [14]

I hope this helps you

7 0

3 years ago

a wire of length 200 cm is cut into two parts and each part is bent to form a square.If the area of the larger square is 9 times

diamong [38]

Answer:

The perimeter of the larger square is $150cm.$

Step-by-step explanation:

First of all, let one part of it be " $x$ "

and the other part of it " $200-x$ "

Now to solve this :

The area of the square = $L^2$

The area of one part of the square = $x^2$

The area of the other part of the square = $(200-x)^2$

$9x^2= (200-x)^2\\9x^2=40000-400x+x^2$

Now, add, $-4x^2$ to both the sides :

$9x^2-9x^2=40000-400x+x^2-9x^2\\-1(8x^2+400x-40000)=0$

Now, take out the "8" which is common :

$-8(x^2+50x-5000)=0$

Now, divide it by $-8$ :

$x^2+100x-50x-5000=0\\x(x+100)-50(x+100)=0\\(x+100)(x-50)=0\\$

$x=-100$ or $50$

So, now we know that :

One of the part is = $50cm$

And the other part is = $150cm$

Thus the perimeter of the larger square is = $150cm$

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3 years ago

You deposit $5000 in an account earning 8% interest compounded monthly. How much will you have in the account in 15 years?

Rasek [7]

$\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$5000\\ r=rate\to 8\%\to \frac{8}{100}\dotfill &0.08\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{monthly, thus twelve} \end{array}\dotfill &12\\ t=years\dotfill &15 \end{cases}$

$\bf A=5000\left(1+\frac{0.08}{12}\right)^{12\cdot 15}\implies A=5000(1.00\overline{66})^{180}\implies A\approx 16534.61$

5 0

3 years ago