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kaheart [24]
3 years ago
11

A car insurance policy has a $500.00 deductible for comprehensive and a $1000.00 deductible for liability. Shaun gets into an ac

cident. The damage to his car is $600.00 and the damage to the other person's car is $1100.00.
How much does Shaun need to pay for damage?
Mathematics
1 answer:
muminat3 years ago
8 0

Answer:

He needs to pay $200

Step-by-step explanation:

Comprehensive: his car- 600-500=$100

Liability:other person- 1100-100=$100

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Find the slope (-10,3) (5,10)
barxatty [35]

Answer:

idk

Step-by-step explanation:

i don't know man how can I answer

8 0
3 years ago
(please zoom / zoom out if needed to see question. (: )
eduard
You can find the area of the rectangle and the triangle separately and then add them together which would result in 330in. I personally do not think you should use the trapezoid formula even though they said it is a trapezoid (a trapezoid is usually not shaped like that) but if you want to it would result in 270in. 

3 0
3 years ago
Based on the graph, what is the initial value of the linear relationship?
alex41 [277]

Answer: two over three

Step-by-step explanation:

y=ax+b

line intercepts y at (0,-2)

Therefore, y=ax-2

Substitute x = 3 in y =ax-2

y=3a-2

To find the x-intercept, y = 0

3a-2=0\\3a=2\\a=\frac{2}{3}

The slope is 2/3

y-intercept is -2

So two over three

4 0
3 years ago
A model for tumor growth is given by the Gompertz equation dV dt = a (In b-, In V) V where a >0 and b >0 are constants and
Xelga [282]

Answer:

V(t) = b^{(1-e^{-at})}

Step-by-step explanation:

We are given the following information in the question:

\displaystyle\frac{dV}{dt} = a (In b - In V) V

where a > 0 and b > 0.

\displaystyle\frac{dV}{dt} = a (In b-In V) V\\\\\displaystyle\frac{dV}{dt} = -aV(ln\frac{V}{b})\\\\\frac{dV}{V(ln\frac{V}{b})} = (-a)dt\\\\\text{Put } ln\frac{V}{b} = z\\\\\text{Integrating both sides}\\\\\int \frac{dV}{V(ln\frac{V}{b})} = \int (-a)dt\\\\\text{We get}\\\\\int \frac{dz}{z} = \int (-a)dt\\\\\\\text{where C is the constant of integration}

V(0) = 1~ mm^3\\V(t) = b.e^{e^{-at+C}}\\\text{Putting t =0, V(0) = 1}\\\\V(0) = 1 = b.e^{e^{C}}\\\\V(t) = b^{(1-e^{-at})}

where v(t) is the required tumor volume as a function of time that has an initial tumor volume of V(0) = 1 cubic mm.

5 0
3 years ago
Suppose total benefits and total costs are given by b(y) = 100y − 8y2 and c(y) = 10y2. what is the maximum level of net benefits
olga nikolaevna [1]
Whenever you face the problem that deals with maxima or minima you should keep in mind that minima/maxima of a function is always a point where it's derivative is equal to zero.
To solve your problem we first need to find an equation of net benefits. Net benefits are expressed as a difference between total benefits and total cost. We can denote this function with B(y).

B(y)=b-c
B(y)=100y-18y²

Now that we have a net benefits function we need find it's derivate with respect to y.

\frac{dB(y)}{dy} =100-36y

Now we must find at which point this function is equal to zero.

0=100-36y
36y=100
y=2.8

Now that we know at which point our function reaches maxima we just plug that number back into our equation for net benefits and we get our answer.

B(2.8)=100(2.8)-18(2.8)²=138.88≈139.

One thing that always helps is to have your function graphed. It will give you a good insight into how your function behaves and allow you to identify minima/maxima points.


3 0
3 years ago
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