Let ABCD be a parallelogram such that AB = 10 , BC = 14, and Angle A = 45. Find the area of the parallelogram. Please do not ans
wer in decimal form. Answer using a square root
1 answer:
Answer:
70√2 units²
Step-by-step explanation:
(see attached for reference notes on parallelograms)
we are given ABCD is a parallelogram where
Short Length, AB = 10 units
Long Length, BC = 14 units
Angle A = 45°
The area of the parallelogram is hence,
= AB x BC sin 45°
= 10 x 14 x sin 45
= 140 sin 45° (recall from special angles, that sin 45° = 1/√2)
= 140/√2 (remove radical from denominator by multiplying by √2/√2)
= (140/√2) x (√2/√2)
=70√2 units²
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