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Anvisha [2.4K]
3 years ago
5

A coffee shop sells regular coffee in three sizes. The table shows the sizes of each regular coffee sold throughout the day. Wri

te and solve a system of equations to determine the price of each regular coffee.
a) bajo: $1.60; mediano: $1.82; grande: $2.00

b) bajo: $1.61; mediano: $1.77; grande: $2.03

c) bajo: $1.62; mediano: $1.80; grande: $2.03

d) bajo: $1.65; mediano: $1.79; grande: $2.07
Mathematics
1 answer:
kenny6666 [7]3 years ago
4 0

Answer:

c) bajo: $1.62; mediano: $1.80; grande: $2.03

Step-by-step explanation:

Insert numbers from the table into a linear equation (ignore time column) and use Cramer's Rule.

55x+53y+54z=299.12

17x+22y+25z=117.89

30x+23y+29z=148.97

x, bajo = 1.62

y, mediano = 1.8

z, grande = 2.03

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Answer:

the third side is 5 2/3 in.

s - 1

Step-by-step explanation:

a = side 1

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The answer is here:

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damaskus [11]

Answer:

\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }

Step-by-step explanation:

Hello, please find below my work.

2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0

\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

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