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3 years ago

Which to temperatures have a sum of 0°C?

Mathematics

1 answer:

Murljashka [212]3 years ago

4 0

Answer:

2°C and -2°C

Step-by-step explanation:

A number and its opposite sum to zero. (The "opposite" is the number with a minus sign instead of a plus sign, or vice versa.)

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Geometry/////

Montano1993 [528]

Answer:

A = 388.58 cm^2

Step-by-step explanation:

For a cone whose base has a radius R, and a hypotenuse S, the area is:

A = pi*R^2 + pi*R*S

Where pi = 3.14

In this case, we can see that the diameter is: 15cm

Then the radius, half of the diameter, is:

R = 15cm/2 = 7.5cm

The hypotenuse is 9cm, then S = 9cm

A = 3.14*(7.5cm)^2 + 3.14*(9cm)*(7.5cm) = 388.575 cm^2

Rounding to two decimal places, we need to look at the third one, which is a five, so we need to round up:

A = 388.58 cm^2

3 0

3 years ago

Plz help me Quick l need helpppp

Angelina_Jolie [31]

I’m not really sure but I would have to guess 4.5 because all of the other numbers don’t have decimals

5 0

3 years ago

For the function y=3x2: (a) Find the average rate of change of y with respect to x over the interval [3,6]. (b) Find the instant

nirvana33 [79]

Answer:

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

Step-by-step explanation:

a) Geometrically speaking, the average rate of change of $y$ with respect to $x$ over the interval by definition of secant line:

$r = \frac{y(b) -y(a)}{b-a}$ (1)

Where:

$a$ , $b$ - Lower and upper bounds of the interval.

$y(a)$ , $y(b)$ - Function exaluated at lower and upper bounds of the interval.

If we know that $y = 3\cdot x^{2}$ , $a = 3$ and $b = 6$ , then the average rate of change of $y$ with respect to $x$ over the interval is:

$r = \frac{3\cdot (6)^{2}-3\cdot (3)^{2}}{6-3}$

$r = 27$

The average rate of change of $y$ with respect to $x$ over the interval $[3,6]$ is 27.

b) The instantaneous rate of change can be determined by the following definition:

$y' = \lim_{h \to 0}\frac{y(x+h)-y(x)}{h}$ (2)

Where:

$h$ - Change rate.

$y(x)$ , $y(x+h)$ - Function evaluated at $x$ and $x+h$ .

If we know that $x = 3$ and $y = 3\cdot x^{2}$ , then the instantaneous rate of change of $y$ with respect to $x$ is:

$y' = \lim_{h \to 0} \frac{3\cdot (x+h)^{2}-3\cdot x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{(x+h)^{2}-x^{2}}{h}$

$y' = 3\cdot \lim_{h \to 0} \frac{2\cdot h\cdot x +h^{2}}{h}$

$y' = 6\cdot \lim_{h \to 0} x +3\cdot \lim_{h \to 0} h$

$y' = 6\cdot x$

$y' = 6\cdot (3)$

$y' = 18$

The instantaneous rate of change of $y$ with respect to $x$ at the value $x = 3$ is 18.

5 0

3 years ago

What is the approximate distance between two points with coordinates (3, 5) and (-4, -8)? Round your answer to the nearest hundr

Anika [276]

There is a problem,in order to solve this u need a cordanite bride for them to go on.

3 0

3 years ago

Read 2 more answers

Maricella solves for x in the equation 4x-2(3x-4)+4=-x+3(x+1)+1. She begins by adding –4 + 4 on the left side of the equation an

Elodia [21]

Maricella’s strategy is incorrect as the values added on the left and right side of the equation changes the original equation $4x-2(3x-4)+4=-x+3(x+1)+1$ to $4x-2(3x-4)+4=-x+3(x+1)+3$ .

Further explanation:

Maricella begin by adding $-4+4$ on the left side of the equation and $1+1$ on the right side of the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ .

The value added on the left is equal to zero so it does not change the equation but the value added on the right is 2, a non-zero digit so it changes the equation as shown below.

$4x-2(3x-4)+4-4+4=-x+3(x+1)+1+1+1\\4x-2(3x-4)+4+0=-x+3(x+1)+1+2\\4x-2(3x-4)+4=-x+3(x+1)+3$

Therefore, the strategy used by Maricella will change the equation and so the solution of the equation will be incorrect.

One way of solving such a linear equation is by adding or subtracting the required value on each side of the equation. and then simplifying the further equation.

Similarly, the other way to solve any linear equation is by separating the variable terms on one side of the equation and constant terms on the other side of the equation.

After this simplify the linear equation to obtain the solution of the equation for $x$ .

Whereas Maricella’s strategy fails to solve the equation $4x-2(3x-4)+4=-x+3(x+1)+1$ since the values added and subtracted in the equation changes the original equation completely.

Learn more:

1. Linear equation application brainly.com/question/2479097

2. To solve one variable linear equation brainly.com/question/1682776

3. Binomial and trinomial expression brainly.com/question/1394854

Answer details

Grade: Middle school

Subject: Mathematics

Chapter: Linear equation

Keywords: equation, linear equation, Maricella, right side, left side, strategy, solve for $x$ , adding, subtracting, variable, constant, solution of the equation, value, original equation, variable terms, constant terms.

4 0

2 years ago

Read 2 more answers