Answer:
![units^{2}](https://tex.z-dn.net/?f=units%5E%7B2%7D)
Step-by-step explanation:
Given Data:
a = 7+3+7 =17 units
b = 3 units
h = 8 units
To Find Out:
Area of trapezoid = ?
Formula:
![A = \frac{a+b}{2}h](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Ba%2Bb%7D%7B2%7Dh)
Solution:
![A = \frac{a+b}{2}*h](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7Ba%2Bb%7D%7B2%7D%2Ah)
![A = \frac{17+3}{2}*8](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B17%2B3%7D%7B2%7D%2A8)
![A = \frac{20}{2}*8](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B20%7D%7B2%7D%2A8)
![A =10*8](https://tex.z-dn.net/?f=A%20%3D10%2A8)
![units^{2}](https://tex.z-dn.net/?f=units%5E%7B2%7D)
<u>Answer:</u>
The volume of a pyramid is ![2406.16 cm^3](https://tex.z-dn.net/?f=2406.16%20cm%5E3)
<u>Explanation:</u>
We know that volume of a square based pyramid is given by the formula,
![\mathrm{V}=\mathrm{a}^{2} \frac{h}{3}](https://tex.z-dn.net/?f=%5Cmathrm%7BV%7D%3D%5Cmathrm%7Ba%7D%5E%7B2%7D%20%5Cfrac%7Bh%7D%7B3%7D)
where V = Volume
a = base length = 17.2cm (given)
And h = height of the pyramid = 24.4cm
So,
![V=17.2^{2} \frac{24.4}{3}](https://tex.z-dn.net/?f=V%3D17.2%5E%7B2%7D%20%5Cfrac%7B24.4%7D%7B3%7D)
=>
which is the volume of the given pyramid .
F (-2)=8-4×-4=+16
f(x)=8 so 8 =8-4x so x=0
it is liner algebra . I will send you the graph and every thing later . like in 5 min .