Answer: If ∡PQR = 82°, and the ray QS bisects it, it cuts ∡PQR into two equal halves, ∡PQS and ∡RQS, each of which is then 82/2, or 41°.
600 and 60 I do not know what to do
I really hope this helps you!
Answer:
Step-by-step explanation:
angular frequency
ω = 2π/ T = 2π/4 = π/2 rad/s
A = 7 inch
Starts at rest (maximum swing, |A| = 7) so cosine function is easiest
x = -7cos(πt/2)