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Citrus2011 [14]
3 years ago
14

Q = 1/2 nv2

SAT
1 answer:
ArbitrLikvidat [17]3 years ago
6 0

Answer:

<em>2.25 or 9/4.</em>

Explanation:

To solve this problem, you need to set up to equations with variables. Let q1 be the dynamic pressure of the slower fluid moving with velocity v1, and let q2 be the dynamic pressure of the faster fluid moving with velocity v2. Then,

v2 = 1.5v1

Given the equation q =  1 /2

nv2, substituting the dynamic pressure and velocity of the faster fluid gives q2 = 1 /2  n(v2)^2. Since v2 = 1.5v1, the expression 1.5v1 can be substituted for v2 in this equation, giving q2 =  1 /2  n(1.5v1)^2. By squaring 1.5, you can rewrite the previous equation as:

q2 = (2.25)( 1 /2 ) n(v1)^2=(2.25)q1

Therefore, the ratio of the dynamic pressure of the faster fluid is

q2 /q1  =  2.25q1 /q1  = 2.25

<em>The final answer is 2.25 or 9/4.</em>

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<h3>Definition of percentage by mass</h3>

The percentage by mass expresses the concentration and indicates the amount of mass of solute present in 100 grams of solution.

In other words, the percentage by mass of a component of the solution is defined as the ratio of the mass of the solute to the mass of the solution, expressed as a percentage.

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<h3>This case</h3>

Because percent by mass indicates the ratio of solute to solution based on mass, if the sample has twice the mass of the first sample, the ratio remains constant.

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