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2 years ago

10

PLEASE HELP, will give brainliest if you answer consider the function represented by the equation 16b = 4r - 12. write the equat

ion in function notation, where b is the independent variable. Must show work for full credit

1 answer:

liubo4ka [24]2 years ago

3 0

Answer:b=1/4r-3/4

Step-by-step explanation:

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The sum of X and fifteen

zhuklara [117]

x+15

depends on the value of x

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2 years ago

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Nataly [62]

Answer:

babysitting = $9

working at coffeehouse = $12

x = hours for babysitting

y = hours at coffeehouse

minimum = ≥

9x + 12y ≥ 240

Step-by-step explanation:

just a short note on which symbol you should use when you see these words in inequality questions:

i) use ≥

-more than or equal to

-not less than

-at least

-minimum

ii) use >

-more than

-greater than

iii) use ≤

-less than or equal to

-not more than

-at most

-maximum

iv) use <

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2 years ago

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

$(a,b)=\left \{ x\in\Re : a$

2. Functions

1) $\Re \rightarrow \Re \\ f(x)=x$

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2) $\Re\geq0\rightarrow\Re , f(x)=x+1\\$

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3) $f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)$

The cosine function is not injective, bijective nor surjective.

4) $f:\Re\rightarrow\Re \:f(x)=ex$

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5) Quite unclear format

$6) \:f:\Re\rightarrow(0,\infty), f(x) =ex$

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

$7) f:\Re\geq 0 \rightarrow \Re\geq0, f(x) =x^{4}$

Not injective nor surjective therefore not bijective too.

$8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}$

$f(-1)=1, f(2)=4, f(-3)=9$

Injective (one to one), Surjective, and Bijective.

$10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.$

Surjective.

$11.f:R\geq 0[-1,1], f(x) = 0\\$

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

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2 years ago

Which illustrates the construction of a perpendicular to a line from a point on the line?

quester [9]

I believe the correct answer from the choices listed above is the last option. The last option clearly describes the illustration of the construction of a perpendicular to a line from a point on the line where you start on a point in the line. Using an arbitrary radius, draw arcs intersecting the line <span> at two points. </span>
Hope this answers the question. Have a nice day.

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2 years ago

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Graph the quadratic function <br> F(x)=3x^2+6x-24

Oliga [24]

For this case we have the following function:
F (x) = 3x ^ 2 + 6x-24
We observe that it is a quadratic equation.
The graph is therefore a parabola.
Its cut points are:
(-4, 0)
(2, 0)
Answer:
See attached image to see graph of the function

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2 years ago