Answer:
b = 80
Step-by-step explanation:
Given that,
x² + bx - 81
To find,
value of b
What is factorable?
A polynomial equation with highest degree 2 is if factorable when
- we can find two terms which when multiples = -81x², <em> ( x² * - 81 = -81x² ) </em>
- and when add = bx
possible factors:
- -1x * 81x = -81x² (Accepted)
- 1x * -81x= -81x² (rejected)
- 9x * -9x = -81x² (rejected)
- -9x * 9x = -81x² (rejected)
Only when -1x , 81x is added -1x + 81x = 80x
so, bx = 80x
b = 80
<h3>The equation is x² + 80x - 81</h3>
The function f(x) = 5x² + 40x is a parabola. Then the vertex of the parabola will be at (–4, –80).
<h3>What is the parabola?</h3>
It is the locus of a point that moves so that it is always the same distance from a non-movable point and a given line. The non-movable point is called focus and the non-movable line is called the directrix.
The function f(x) = 5x² + 40x
Then add and subtract 80, then we have
f(x) = 5x² + 40x + 80 – 80
f(x) = 5(x² + 8x + 16) – 80
f(x) = 5(x + 4)² – 80
The vertex of the parabola will be at (–4, –80).
More about the parabola link is given below.
brainly.com/question/8495504
The answer is A
Sine you are subtracting,
x-x=o
1- -8 =9 since subtracting a negative is adding a positive.
So the answer is 9/x-1
Answer:
Step-by-step explanation:
Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6
Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is 2 .
Answer:
A,B,C
Step-by-step explanation:
in these quadrilaterals, the diagonals bisect each other paralellogram, rectangle, rhombus, square
in these quadrilaterals, the diagonals are congruent rectangle, square, isosceles trapezoid
in these quadrilaterals, each of the diagonals bisects a pair of opposite angles rhombus, square
