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Mashcka [7]
3 years ago
15

The formula for the area of a triangle is

Mathematics
1 answer:
umka21 [38]3 years ago
6 0

Answer:

b = (2A)/h

Step-by-step explanation:

With area formula for triangle:   A = (1/2)*b*h

Solve for b

2*A = 2*(1/2)*b*h

2A = bh

2A / h = b

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Enter the equations of the asymptotes for the function f(x).<br><br> f(x)= 3/x−7 + 2
Alexxx [7]

Answer:

x = 7, y = 2

Step-by-step explanation:

I assume it is 3/(x-7) + 2.

When x = 7, there is an asymptote because it is undefined.

When y = 2, there is also one, because 3/(x-7) is never 0.

These are the only ones.

3 0
4 years ago
Fill in the blanks to show the product.
Fittoniya [83]

Answer:

Hope this is helpful for you

5 0
3 years ago
4. "Ten less than the quotient of a number and<br>3 is 8."​
Nookie1986 [14]

Answer:

3x - 10 = 8

Step-by-step explanation:

Let's reconsider the wording of this problem.

"Ten less than the quotient of a number and

3 is 8."​

From less, we can assume 10 is being subtracted from something.

We have:

-10

Next, we know that the quotient is the sum of a multiplication problem. So, we know 3 has to be multiplied by something. We can see that the text says 'a number'. If they don't give us the value we can guess that it is the variable x.

Now:

3x - 10

From 'is 8' we know that must be the final sum of the equation.

Finally:

3x - 10 = 8

7 0
3 years ago
What is the greatest common factor of 8 and 13
Svetlanka [38]

Answer:

GCF=1

Step-by-step explanation:

Lets factor both numbers:

the factors of 8:

1,2,4,8

the factors of 13:

1,13

The largest number in common is 1

8 0
3 years ago
Which relationship is a direct variation?
Setler79 [48]

Option A is the relationship which shows a direct variation.

Step-by-step explanation:

The direct variation is a relationship between two variables in which one is the multiple of the other. It is given by the relation

\frac{y}{x}=k

Option A:

For x=2 and y=1,

\frac{y}{x}=\frac{1}{2}

For x=4 and y=2,

\frac{y}{x}=\frac{2}{4}= \frac{1}{2}

Since, the constant k is equal for all the values of x and y in the table, this relationship is a direct variation.

Option B:

For x=2 and y=4,

\frac{y}{x}=\frac{4}{2}= 2

For x=4 and y=16,

\frac{y}{x}=\frac{16}{4}  =4

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option C:

For x=1 and y=3

\frac{y}{x} =\frac{3}{1} =3

For x=2 and y=5

\frac{y}{x} =\frac{5}{2}

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Option D:

For x=1 and y=-1

\frac{y}{x} =\frac{-1}{1} =-1

For x=2 and y=2

\frac{y}{x} =\frac{2}{2} =1

Since, the values of constant k is not equal for all the values of x and y in the table, this relationship is not a direct variation.

Thus, Option A is the relationship which shows direct variation.

7 0
3 years ago
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