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3 years ago

2m-jk/p=G solve for M

Mathematics

1 answer:

Katen [24]3 years ago

4 0

Answer:

$m = \frac{g + \frac{jk}{p} }{2}$

Step-by-step explanation:

Given equation:

$2m - \frac{jk}{p} = g$

Add jk/p to both sides:

$2m = g + \frac{jk}{p}$

Divide by 2:

$m = \frac{g + \frac{jk}{p} }{2}$

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Polynomial of degree 3 with three distinct real zeros and a positive leading coefficient

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3 years ago

1. Which of these fractions has the greatest value?" Mark only one oval. 7/12 5/6 2/3

ddd [48]

Answer:

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Step-by-step explanation:

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2 years ago

A classmate simplified a rational expression below

lara31 [8.8K]

<h2>Part a) </h2><h2>Explain the error in this simplification.</h2>

Given the simplified expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$\:1-2x-4=x^2-x-2$

$-2x-3=x^2-x-2\:\:$

$0=x^2-2x-2\:\:$

$0=\left(x-1\right)\left(x-1\right)$

$x=1$

<u><em>Identifying the Main Error</em></u>

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$ ← ERROR Starts here

<u><em>Here is the Explanation of the Error </em></u>

<u><em /></u> $\mathrm{The\:equation\:should\:have\:been\:Multiplied\:by\:LCM=}\left(x-2\right)\left(x+2\right)$ <em>. </em>In your case you wrongly multiply the equation.

<em><u>CORRECTION</u></em>

<em>HERE IS HOW YOU SHOULD HAVE MULTIPLIED BY </em><em>LCM = (x-2)(x+2):</em>

<em />

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

<h2>Part b) </h2><h2>Show your work as you correct the error</h2>

Here is the complete correction of the error.

Considering the expression

$1-\frac{2}{x-2}=\frac{x+1}{x+2}$

$\mathrm{Find\:Least\:Common\:Multiplier\:of\:}x-2,\:x+2:\quad \left(x-2\right)\left(x+2\right)$

$1\cdot \left(x-2\right)\left(x+2\right)-\frac{2}{x-2}\left(x-2\right)\left(x+2\right)=\frac{x+1}{x+2}\left(x-2\right)\left(x+2\right)$

$\left(x-2\right)\left(x+2\right)-2\left(x+2\right)=\left(x+1\right)\left(x-2\right)$

$x^2-2x-8=x^2-x-2$

$x^2-2x-8+8=x^2-x-2+8$

$x^2-2x=x^2-x+6$

$-x=6$

$\frac{-x}{-1}=\frac{6}{-1}$

$x=-6$

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3 years ago

I am stuck on the question because I don't know it.

artcher [175]

Answer:

2x^2-29 its A

Step-by-step explanation:

5x-5=-25

2x-2=-4

-25+-4=-29

X x X=x^2

X^2 + X^2=2x^2

6 0

3 years ago

Brooke found the equation of the line passing through the points (–7, 25) and (–4, 13) in slope-intercept form as follows.

Arturiano [62]

For this case we have that by definition, the equation of a line in the slope-intersection form is given by:

$y = mx + b$

Where:

m: It's the slope

b: It is the cut-off point with the y axis

$m = \frac {y2-y1} {x2-x1}$

We have the following points:

$(x1, y1): (- 7,25)\\(x2, y2): (- 4,13)$

Substituting the values: $m = \frac {13-25} {- 4 - (- 7)} = \frac {-12} {- 4 + 7} = \frac {-12} {3} = - 4$

Thus, the line is of the form:

$y = -4x + b$

We substitute one of the points and find "b":

$13 = -4 (-4) + b\\13 = 16 + b\\b = 13-16 = -3$

Finally we have to:

$y = -4x-3$

Answer:

The equation es $y = -4x-3$

6 0

3 years ago

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