X = 89
Used the Pythagorean theorem (a squared plus b squared equals c squared)
Arccos(cos 7pi/2)
cos 7pi/2 = cos 630 = cos (630-360) = cos 270 = 0
arccos(0) = 90 since cos 90 = cos 270
(x): 0 - 30 - 45 - 60 - 90
sin (x) 0 - 1/2 - 1/2 √3 - 1/2 √3 - 1
cos (x) 1 - 1/2 √3 - 1/2 √3 - 1/2 - 0
tan (x) 0 - 1/√3 - 1 - √3 - ∞
Rules for sin cos tan value in each quadrant :
quadrant = I(0-90) - II (90-180)- III(180-270) - IV(270-360)
sin (x) = positive- positive - negative - negative
cos (x) = positive- negative- negative - positive
tan (x) = positive- negative- positive - negative
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Answer
2x-y=4
Hope this helps!!!
Answer:
x = 2√7, y = √21
Step-by-step explanation:
The textbook has right angles, so we can use Pythagorean theorem to find the missing lengths.
For the triangle on top of the textbook:
c² = a² + b²
8² = 6² + x²
64 = 36 + x²
28 = x²
x = √28
x = 2√7
For the triangle on the side of the textbook:
c² = a² + b²
7² = x² + y²
49 = 28 + y²
21 = y²
y = √21