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Reil [10]
3 years ago
14

What is the slope of the line that passes through points (0,5)(2,2)

Mathematics
1 answer:
san4es73 [151]3 years ago
8 0

Answer:

m = (2 - 5) / (2 - 0) = -3/2 = -1.5

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Find the quotient.<br><br> 54÷1112 =
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3 years ago
A cafeteria serves lemonade that is made from a powdered drink mix. There is a proportional relationship between the number of s
Vitek1552 [10]

All the answers to the given parts are mentioned below -

<h3>What is the general equation of a Straight line? How it represents a proportional relationship?</h3>

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] is the y - intercept i.e. the point where the graph cuts the [y] axis.

y = mx also represents direct proportionality. We can write [m] as -

m = y/x

OR

y₁/x₁ = y₂/x₂

We have a cafeteria serves lemonade that is made from a powdered drink mix. There is a proportional relationship between the number of scoops of powdered drink mix and the amount of water needed to make it. For every 2 scoops of mix, one-half gallon of water is needed, and for every 6 scoops of mix, one and one-half gallons of water are needed.

We can write the proportional relationship as -

y = kx

Now, from the given information, we can write -

2 scoops need 0.5 gallon of water

6 scoops need 1.5 gallon of water

So -

k = 2/0.5

k = 2/(1/2)

k = 2 x 2 = 4

Equations that represents the relationship can be written as -

y = 4x + c

Now, 2 scoops need 0.5 gallon of water.

2 = 4 x 1/2 + c

2 = 2 + c

c = 0

So, the equation will be y = 4x.

Graph of y = 4x is attached at the end.

For 10 scoops of water -

10 = 4x

x = 2.5 gallons of water is needed.

Therefore, all the answers to the given parts are mentioned above.

To solve more questions on proportional relationship, visit the link below-

brainly.com/question/12917806

#SPJ1

5 0
1 year ago
Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th
STatiana [176]

We can find the acceleration via

{v_f}^2-{v_i}^2=2a\Delta x

We have

\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)

\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}

Then by definition of average acceleration,

a_{\rm ave}=\dfrac{v_f-v_i}t

so that

-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t

\implies\boxed{t=6.33\,\mathrm s}

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2

Then

\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2

\implies\boxed{t=6.33\,\mathrm s}

7 0
3 years ago
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