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Ksenya-84 [330]

4 years ago

12

Mr Baker wants to divide his class into smaller, equal-sized groups of students. However, he finds that his class cannot be divi

ded evenly into any size group except for individual groups of 1

1 answer:

Sloan [31]4 years ago

8 0

Question is incomplete below is complete question.

Mr Baker wants to divide his class into smaller, equal-sized groups of students. However, he finds that his class cannot be divided evenly into any size group except for individual groups of 1.Complete the statements below about the number of students in Mr Baker's class.

Answer:

The number of students in his class must be a prime number.

Step-by-step explanation:

Given:

Mr Baker wants to divide his class into smaller and equal-sized group of students.

Also class cannot be divided evenly into any size group except for individual groups of 1.

If he cannot divide his team into smaller equal sized groups, that means that it cannot be divided by a number. Prime numbers are numbers that can only be divided evenly by themselves and 1.

Hence from above we can say that,

The number of students in his class must be a prime number.

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Suppose that Y1, Y2,..., Yn denote a random sample of size n from a Poisson distribution with mean λ. Consider λˆ 1 = (Y1 + Y2)/

Burka [1]

Answer:

The answer is " $\bold{\frac{2}{n}}$ ".

Step-by-step explanation:

considering $Y_1, Y_2,........, Y_n$ signify a random Poisson distribution of the sample size of n which means is λ.

$E(Y_i)= \lambda \ \ \ \ \ and \ \ \ \ \ Var(Y_i)= \lambda$

Let assume that,

$\hat \lambda_i = \frac{Y_1+Y_2}{2}$

multiply the above value by Var on both sides:

$Var (\hat \lambda_1 )= Var(\frac{Y_1+Y_2}{2} )$

$=\frac{1}{4}(Var (Y_1)+Var (Y_2))\\\\=\frac{1}{4}(\lambda+\lambda)\\\\=\frac{1}{4}( 2\lambda)\\\\=\frac{\lambda}{2}\\$

now consider $\hat \lambda_2$ = $\bar Y$

$Var (\hat \lambda_2 )= Var(\bar Y )$

$=Var \{ \frac{\sum Y_i}{n}\}$

$=\frac{1}{n^2}\{\sum_{i}^{}Var(Y_i)\}\\\\=\frac{1}{n^2}\{ n \lambda \}\\\\=\frac{\lambda }{n}\\$

For calculating the efficiency divides the $\hat \lambda_1 \ \ \ and \ \ \ \hat \lambda_2$ value:

Formula:

$\bold{Efficiency = \frac{Var(\lambda_2)}{Var(\lambda_1)}}$

$=\frac{\frac{\lambda}{n}}{\frac{\lambda}{2}}\\\\= \frac{\lambda}{n} \times \frac {2} {\lambda}\\\\ \boxed{= \frac{2}{n}}$

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3 years ago

Need answers <br> Chapter 3 test on big ideas math

wariber [46]

Answer:

obtuse angle

Step-by-step explanation:

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3 years ago

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3x+2y=7 y=3x-19 could someone show me a step by step for this equation for substitution

Vitek1552 [10]

Answer:

$\boxed {\boxed {\sf (5,-4)}}$

Step-by-step explanation:

We are given the equations:

$3x+2y=7 \\y=3x-19$

Since we know what y is equal to, we can substitute that expression in for y in the first equation.

$3x+2(3x-19)=7$

Distribute the 2. Multiply each term inside the parentheses by 2.

$3x+(2*3x)+ (2*-19)=7$

$3x+6x+-38= 7$

Combine the like terms (the terms with variables).

$9x-38=7$

Since we are solving for x, we must isolate the variable. 38 is being subtracted and the inverse of subtraction is addition. Add 38 to both sides.

$9x-38+38=7+38 \\9x=7+38\\9x=45$

Now x is being multiplied by 9. The inverse of multiplication is division. Divide both sides by 5.

$9x/9=45/9\\x=45/9\\x=5$

Now we know what x is equal to and can substitute the value into the second equation.

$y=3x-19$

$y=3(5)-19$

Multiply.

$y=15-19$

Subtract.

$y= -4$

Coordinate points are written as (x,y). Therefore, the solution is (5, -4).

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3 years ago

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Dmitry [639]

Answer:

A. c = 16d + 18

Step-by-step explanation:

Solution:

we are given with a data table and we have been asked to find the function rule.

If we closely observe the table then we find that table is following the below function rule

Check for

Check for

Check for

Check for

Hence the correct option is c = 16d + 18

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maddymcg408

Virtuoso

250 answers

3.8K people helped

Answer:

c = 16d + 18

Step-by-step explanation:

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Answer: positive association and linear association

Step-by-step explanation:

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