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vlada-n [284]
4 years ago
8

HELP!!!

Mathematics
1 answer:
Vika [28.1K]4 years ago
4 0

She purchased 4 children’s tickets. To solve you find out that she buys 3 adult tickets worth $27. Then add $4 until $43.
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What is the length of a car if the length on the scale model car is 17cm and the scale is 2cm : 50cm?
e-lub [12.9K]
425 cm. The ratio is 17 : x is equal to 2cm : 50cm. You use cross multiplication to solve. 17 times 50 = 2 times x.
850 = 2x
425 = x

4 0
3 years ago
Mr.Richards wants to buy disposable masks for his family. Blue mask cost 1.50 and white mask cost 2.50. He has 45 dollars to spe
Colt1911 [192]

Answer:

he would have to buy the blue masks at 1.50 each

Step-by-step explanation:

you divide

45 \div 20 = 2.25

witch equals 2.25 so he can only spend $2.25 per mask so that's how i found out he can only buy the blue masks

8 0
3 years ago
What is the quotient<br> when dividing 16 by 4/5<br>​
PolarNik [594]

Answer:

20

Step-by-step explanation:

5 0
3 years ago
A line pases through the point (4,-1) and has a y interespt of of -3
GenaCL600 [577]
Ok and wisjjsjsjsnsj
4 0
3 years ago
1. Determine the discriminant and nature of roots of each quadratic equation.
Fiesta28 [93]

Answer:

Please check the explanation.

Step-by-step explanation:

The general quadratic equation is

ax²+bx+c=0

The discriminant = D = b² - 4ac

When b² - 4ac = 0 there is one real root.

When b² - 4ac > 0 there are two real roots.

When b² - 4ac < 0 there are two complex roots.

1) x² -6x + 9=0

On comparing with given quadratic equation x² -6x + 9=0

a = 1, b=-6, c=9

D = b² - 4ac

   = (-6)² - 4(1)(9)

   = 36 - 36

   = 0

D = 0

Thus, there is one real root of quadratic equation x² -6x + 9=0.

2) x² -4x + 3=0

On comparing with given quadratic equation x² -4x + 3=0

a = 1, b=-4, c=3

D = b² - 4ac

   = (-4)² - 4(1)(3)

   = 16 - 12

   = 4

D > 0

Thus, there are two real roots of quadratic equation x² -4x + 3=0.

3)  x² -7x - 4=0

On comparing with given quadratic equation x² -7x - 4=0

a = 1, b=-7, c=-4

D = b² - 4ac

   = (-7)² - 4(1)(-4)

   = 49 + 16

   = 65

D > 0

Thus, there are two real roots of quadratic equation x² -7x - 4=0

4)  2x² +3x +5=0

On comparing with given quadratic equation 2x² +3x +5=0

a = 2, b=3, c=5

D = b² - 4ac

   = (3)² - 4(2)(5)

   = 9 - 40

   = -31

D < 0

Thus, there are two complex roots of quadratic equation 2x² +3x +5=0

8 0
3 years ago
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