The point of interest is where the graphs cross.
(x, y) = (11, 5)
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Linear equations can be solved by any of a variety of methods. Using substitution for y, you have
.. 7x +3(27 -2x) = 92
.. x = 11 . . . . . . . . . . . . . collect terms, subtract 81
Then
.. y = 27 -2*11 = 5
(x, y) = (11, 5)
_____
Linear equations can be solved by any of a variety of methods. Using substitution for y, you have
.. 7x +3(27 -2x) = 92
.. x = 11 . . . . . . . . . . . . . collect terms, subtract 81
Then
.. y = 27 -2*11 = 5