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Molodets [167]
3 years ago
15

Which literal equation is equivalent to 1.4 = kx?

Mathematics
1 answer:
Fantom [35]3 years ago
7 0
The answer is C.k = 1.4 / x :))
You might be interested in
What value(s) of x will make x to the 2nd power =9 true​
Anastaziya [24]

Answer:

x = 3 , X = -3

In x 2 = 9 , you need to get rid of the power of 2 in order to isolate just x This involves finding the square root. √ x 2 = x However there are 2 possible answers to a square root, a positive or a negative answer. x = ± √ 9 x = ± 3

3 0
3 years ago
Which statements about the graph of the function f(x) = -x2 - 4x + 2 are true? Select three options.
Nady [450]

Answer:

Domain is all real numbers.

The range is \{y|y\le 6\}

The function is increasing over (-\infty,-2).

The function is decreasing over (-2,\infty)

The function has a positive y-intercept.

-----------------This is a guess if I had interpreted your choices correctly:

Second option: The range is \{y|y\le 6\}

Third option:  The function is increasing over (-\infty,-2).

Last option:  The function has a positive y-intercept.

I can't really read some of your choices. So you can read my above and determine which is false. If you have a question about any of what I said above please let me know.

Note: I guess those 0's are suppose to be infinities? I hopefully your function is f(x)=-x^2-4x+2.

Step-by-step explanation:

f(x)=-x^2-4x+2 is a polynomial function which mean it has domain of all real numbers.  All this sentence is really saying is that there exists a number for any value you input into -x^2-4x+2.

Now since the is a quadratic then it is a parabola. We know it is a quadratic because it is comparable to ax^2+bx+c, a \neq 0.

This means the graph sort of looks like a U or an upside down U.

It is U, when a>0.

It is upside down U, when a.

So here we have a=-1 so a which means the parabola is an upside down U.  

Let's look at the range.  We know the vertex is either the highest point (if a) or the lowest point (if a>0).

The vertex here will be the highest point, again since a.

The vertex's x-coordinate can be found by evaluating \frac{-b}{2a}:

\frac{-(-4)}{2(-1)}=\frac{4}{-2}=-2.

So the y-coordinate can be found by evaluate -x^2-4x+2 for x=-2:

-(-2)^2-4(-2)+2

-(4)+8+2

4+2

6

So the highest y-coordinate is 6.  The range is therefore (-\infty,6].

If you picture the upside down U in your mind and you know the graph is symmetrical about x=-2.

Then you know the parabola is increasing on (-\infty,-2) and decreasing on (-2,\infty).

So let's look at the intevals they have:

So on (-\infty,-2) the function is increasing.

Looking on (-4,\infty) the function is increasing on (-4,-2) but decreasing on the rest of that given interval.

The function's y-intercept can be found by putting 0 in for x:

-(0)^2-4(0)+2

-0-0+2

0+2

2

The y-intercept is positive since 2>0.

8 0
4 years ago
Bacgvcfbbnnnbvvbbbgggggggggggggggg
REY [17]

Answer:

2)  x=u/2+1

4)  a=g/c

6)  x=g-c

8)  =g/c

Step-by-step explanation:

hope this is helpful

5 0
3 years ago
Good morning....I guess??​
Simora [160]

Answer:

goodnight...efhfcbrbxbcjbxbxbfj

5 0
4 years ago
Read 2 more answers
Question
Serggg [28]

Answer:

i think two months im not sure tho

Step-by-step explanation:

5 0
3 years ago
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