3 years ago

(2×²y²)⁰ I need help with exponents

Mathematics

2 answers:

balandron [24]3 years ago

7 0

Answer:

Step-by-step explanation:

Any real value to the power of 0 is 1.

Rus_ich [418]3 years ago

4 0

Value to the power of 0 is 1

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$\boxed{\sf \ \ \ (-2x+-9)(1x+3)=-2x^2-15x-27 \ \ \ }$

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Step-by-step explanation:

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$(-2x+-9)(1x+3)=(-2x-9)(x+3)=-2x(x+3)-9(x+3)=-2x^2-6x-9x-27\\=-2x^2-15x-27$

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(2×²y²)⁰ I need help with exponents ​

(2×²y²)⁰ I need help with exponents