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sleet_krkn [62]
3 years ago
15

6b - 1 < -7 or 2b + 1 > 5

Mathematics
1 answer:
bogdanovich [222]3 years ago
3 0
I hope this helps you

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Paul bought 9 total shirts for a total of $72. Tee shirts cost $10 and long sleeve shirts cost $7. How many of each type of shir
sasho [114]
He bought three $10 shirts and six $7 shirts.
4 0
3 years ago
Find the average rate of change of f(x)=2x^2-7x from x=2 to x=5
m_a_m_a [10]

Answer:

7

Step-by-step explanation:

The average rate of change of f(x) in the close interval [ a, b ] is

\frac{f(b)-f(a)}{b-a}

Here [ a, b ] = [2, 5 ]

f(b) = f(5) = 2(5)² - 7(5) = 50 - 35 = 15

f(a) = f(2) = 2(2)² - 7(2) = 8 - 14 = - 6, thus

average rate of change = \frac{15-(-6)}{5-2} = \frac{21}{3} = 7

3 0
3 years ago
A student earned grades of 84, 78, 84, and 72 out of 100 on her four regular tests. She scored 78% on the final exam and 86% on
adelina 88 [10]

If the student received marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade is 81.2 percent.

<h3>What is mean?</h3>

The mean is described as a single number that indicates either the closed value for each item in the collection of data or the mean value for the whole set of data.

On her four regular tests, a student had grades of 84, 78, 84, and 72 out of 100. She received 86 percent on her class projects and 78 percent on the final test.

You may compute the weighted mean as follows:

\rm W_m= 0.4 \times ( \frac{84+78+84+72}{4} )+0.3 \times 78 +0.1 \times 86 + 0.2 \times 87 \\\\ W_m=  81.2 \%

Hence, if the student had marks of 84, 78, 84, and 72 on her four normal tests, her weighted mean grade would be 81.2 percent.

To learn more about the mean refer;

brainly.com/question/22871228

#SPJ1

5 0
2 years ago
How to solve a\10=-10
koban [17]

Answer:

a = - 100

Step-by-step explanation:

Given

\frac{a}{10} = - 10

Multiply both sides by 10 to clear the fraction

a = 10 × - 10 = - 100

4 0
3 years ago
Help!!!!!!!!!!!!!!!!!!!!!!!
Nataly [62]
Hello.

Firstly, let's isolate x on the equation:

\mathsf{f(x) = 3x + 3} \\ \\ \mathsf{y = 3x + 3} \\ \\ \mathsf{-3x = -y + 3} \\ \\ \mathsf{x = \dfrac{-y + 3}{3}}

Now, we can replace 'x' for 'y' and vice-versa:

\mathsf{f^{-1}(x) = \frac{-x + 3}{3}`}

Hope I helped.
4 0
3 years ago
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