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Anit [1.1K]
4 years ago
5

The Law of Universal Gravitation Multiple-choice question #1 is in effect everywhere and for all things that have mass is in eff

ect everywhere for some things that have mass #2 is not in effect everywhere but might influence things that have mass #3 has never been proven
History
1 answer:
Snezhnost [94]4 years ago
3 0
<span>has never been proven</span>
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Describe Philip Johnson’s role in the Navajo Code Talker organization in World War II
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Answer:

Military communications have to be coded to keep them secret from the enemy. However the process of coding and decoding are time consuming processes. Furthermore the codes may be broken by the enemy. Nations have devoted considerable effort trying to create unbreakable codes. In World War II both Germany and Japan thought they had such unbreakable codes, but in fact these codes were broken and their most vital information were readily available to their enemies.

Explanation:

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2. Which statement BEST describes Imre
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He was an opponent of the uprising and was later killed for leading the Hungarian Revolution if 1956.
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With which of the following statements would the author of the passage most likely agree?
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THE ANSWER IS C CAUSE I KNOW IT
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What holiday marks when jesus was put on the cross?
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4 years ago
Find the value of h(45) for the function below.<br> h(x) = {(90 – 5)<br> What’s the value
Rasek [7]

Answer:Inverse Functions

One-to-one

Suppose f : A ⇥ B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c ⇤ A with

a ⌅= c, we are guaranteed that f(a) ⌅= f(c).

Example. f : R ⇥ R where f(x) = x2 is not one-to-one because 3 ⌅= 3

and yet f(3) = f(3) since f(3) and f(3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(x) in more than one point,

then f(x) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate – for example, (2, 3) and

(4, 3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two dierent objects in the domain to the same object

of the target.

If every horizontal line in R2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : R ⇥ R where f(x) = x2. There is a

horizontal line that intersects this graph in more than one point, so f is not

one-to-one.

66

Inverse Functions

One-to-one

Suppose f : A —* B is a function. We call f one-to-one if every distinct

pair of objects in A is assigned to a distinct pair of objects in B. In other

words, each object of the target has at most one object from the domain

assigned to it.

There is a way of phrasing the previous definition in a more mathematical

language: f is one-to-one if whenever we have two objects a, c e A with

a ~ c, we are guaranteed that f(a) $ f(c).

Example. f : IR —* JR where f(x) = x2 is not one-to-one because 3 ~ —3

and yet f(3) = f(—3) since f(3) and f(—3) both equal 9.

Horizontal line test

If a horizontal line intersects the graph of f(.x) in more than one point,

then f(z) is not one-to-one.

The reason f(x) would not be one-to-one is that the graph would contain

two points that have the same second coordinate — for example, (2,3) and

(4,3). That would mean that f(2) and f(4) both equal 3, and one-to-one

functions can’t assign two different objects in the domain to the same object

of the target.

If every horizontal line in JR2 intersects the graph of a function at most

once, then the function is one-to-one.

Examples. Below is the graph of f : JR —, R where f(z) = z2. There is a

horizontal line that intersects this graph in more than one point, so f is not

Explanation:

5 0
3 years ago
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