I just need questions so try your best hope this works
First, substitute.
-9 = 2(-2) - 5
-9 = -4 -5
-9 = -9
Yes, the point (-2, -9) satisfies the equation
Answer:
The product of a linear monomial and a linear binomial is a second degree binomial
Step-by-step explanation:
Examples of linear monomials are:
2x
2a
y
Examples of linear binomials are:
2x+y
x-y
3a+b
x+1
When we take the product of a linear monomial and a linear bbinomial we obtain:
2a(3a+b)=6a²+2ab
y(x+1)=xy+y
y(x-y)=xy-y²
These are all second degree binomials.
Let's follow the transformations that happen to A, to get to A' and A''.
Point A is at (-5, -2)
It moves to (-5, 2) which is where A' is located. Note the x coordinate stays the same while the y coordinate flips from negative to positive. This must mean we applied a reflection over the x axis.
That rule in general is 
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Now compare A'(-5,2) and A''(1,4). We can shift A' 6 units to the right and then 2 units up so we move from A' to A''.
Algebraically this is stated as 
Whatever the x coordinate is, add 6 to it. For the y coordinate, we add on 2.
Applying that rule to B'(-1,2) gets us to

which is the proper location of B''
The same applies to moving C' to C''

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In summary, we started off by reflecting over the x axis. Then we applied the translation rule of "shift to the right 6 units, shift up 2 units".
In terms of algebra, combining the rules
and
will have us end up with 