Answer:
27.98% probability that less than half of them (3 or fewer) would support the Republican candidate
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they support the Republican candidate, or they do not. The people are chosen at random, which means that the probability of them supporting the republican candidate is independent from other people. So we use the binomial probability distribution to solve this problem.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem we have that:
The Republican candidate is supported by 54%. This means that 
Suppose you run a poll of 8 people (randomly choose 8 people). What is the probability that less than half of them (3 or fewer) would support the Republican candidate?
This is
when
.
So

In which





So

27.98% probability that less than half of them (3 or fewer) would support the Republican candidate
Answer:
wouldnt it be 4.2 ?
Step-by-step explanation:
Answer:
2
Step-by-step explanation:
7*4-3*8+2^2-6
7*4-3*8+4-6
28-3*8+4-6
28-24+4-6
4+4-6
8-6
2
Answer:
340
Step-by-step explanation:
-10[5 - ( 30 +
× 3) ÷ 2]
Calculate 4 to the power of 2 and get 16.
-10 
Multiply 16 and 3 to get 48.

Add 30 and 48 to get 78.
-10 
Divide 78 by 2 to get 39.
-10 ( 5 - 39)
Subtract 39 from 5 to get −34.
-10 (-34)
Multiply −10 and −34 to get 340
340
Hope it helps you and have a great day! =D
~sunshine~