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Masteriza [31]
3 years ago
6

Point E is on line segment DF. Given DE = 2x, EF = 2x – 6, and

Mathematics
1 answer:
Kamila [148]3 years ago
8 0

Answer:

EF is 16.  

Step-by-step explanation:

So we know that Point E is somewhere on Line DF. In other words, DE plus EF must equal DF. In an equation, this is:

DF=DE+EF

We are given that DE is 2x, EF is 2x-6, and DF is 3x+5. So, substitute:

(3x+5)=(2x)+(2x-6)

Now, solve for x.

On the right, combine like terms:

3x+5=4x-6

Subtract 4x from both sides:

-x+5=-6

Subtract 5 from both sides:

-x=-11

Divide both sides by -1:

x=11

Now that we know x is 11, substitute this back into the equation for EF to find EF.

EF=2x-6

Substitute 11 for x:

EF=2(11)-6

Multiply:

EF=22-6

Subtract:

EF=16

And we're done!

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