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Monica [59]
3 years ago
7

You are about to take the road test for your​ driver's license. You hear that only 38​% of candidates pass the test the first​ t

ime, but the percentage rises to 76​% on subsequent requests. Estimate the average number of tests drivers take in order to get a license. Your simulation should use at least 20 runs.
Mathematics
1 answer:
OLga [1]3 years ago
7 0

Answer:

Answers may vary but will most likely be close to 2.

Step-by-step explanation

  1.        Given:

                 first test:38%

                 second test:76%

    SIMULATION FIRST TEST

Randomly select a 2-digit number.

If the digit is between 00 and 35 then you passed the test,else you did not pass the test.

SIMULATION SECOND TEST

Randomly select a 2-digit number.

if the digit is between 00 and 75 then you passed the test,else you did not pass the test.

SIMULATION TRIAL

Perform the simulation of the first test.if you did not pass the first test then perform the simulation of the second test.

Record the number of trials needed to pass the first or second test.

Repeat 20 times and take the average of the 20 recorded number of trials

(what is the sum of recorded values divided by 20).

Note:you will most likely obtain a result of about two trials needed.

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First 100 terms of the following sequence 3 ,7 ,11
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Given that a_1 = 3, d = 4

<u>Find the nth term:
</u>
a_n = 3 + 4(n - 1)

a_n = 3 + 4n - 4

a_n =  4n - 1

<u>Find the 100th term:</u>

a_{100} = 4(100) - 1 = 399

<u>Find the Sum:</u>

\text{Sum} = 100(\dfrac{a_1 + a_{100}}{2} )= 100 (\dfrac{3 + 399}{2}) = 20100

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31 miles an hour just divide 527 by 17
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Form a third degree polynomial function with real coefficients such that -9+i and 7 are zeros
jonny [76]
Yes they are that's correct
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3 years ago
Can somebody please help m eits 9th grade math im so confused !
prisoha [69]

Answer:

Option 3: (5, 1)

Step-by-step explanation:

There are several ways of solving for systems of linear equations, either through graphing, substitution, or elimination.  

The graphing method is the easiest, as you only need to plot points on the graph using the y-intercepts and the slopes.  

I will be demonstrating the <u>graphing method</u>.  

Given the systems of linear equations:  

Equation 1:  y = x - 4

where the <u>slope</u>, <em>m</em> = 1, and <u>y-intercept </u>(0, -4).

Equation2: y = -x + 6

where the <u>slope</u>, <em>m </em>= -1, and <u>y-intercept</u> (0, 6).

The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b).

<h3>Graphing Instructions:</h3>

For Equation 1, plot the y-intercept, (0, -4) on the graph. Then use the <u>slope</u>, m = 1 (rise 1 unit, run 1 unit) to plot other points on the graph. Repeat this process until you have enough points to connect a line with.  

Repeat these same procedures for graphing Equation 2, start by plotting its y-intercept at (0, 6), and its slope, m = -1 (down 1 unit, run 1 unit).

<h3>Solution: </h3>

The intersection of both lines occurs at point, (5, 1), which is solution to the given systems of linear equations.  Therefore, the correct answer is the third option, (5, 1).

Attached is the screenshot of the graphed systems of linear equations, where it shows the point of intersection at (5, 1).  

5 0
3 years ago
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