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3 years ago

Can someone help me out please!

Mathematics

1 answer:

nalin [4]3 years ago

3 0

If hugo has 1400 and on the 2 month it is c

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The points A,B and C lie on a straight line

aev [14]

I think 0 but if I am wrong I'm sorry

Step-by-step explanation:

6 0

2 years ago

To solve 9x²-12x+4=49 by using the square root property, you would first rewrite the equation as...

n200080 [17]

Answer:

Step-by-step explanation:

4 0

3 years ago

What is the common denominator of (5/x^2-4) - (2/x+2) in the complex fraction (2/x-2) - (3/x^2-4)/(5/x^2-4) - (2/x+2)

PIT_PIT [208]

9514 1404 393

Answer:

common denominator: (x² -4)
simplified complex fraction: (2x +1)/(9 -2x)

Step-by-step explanation:

It is helpful to remember the factoring of the difference of squares:

a² -b² = (a -b)(a +b)

Your denominator of (x² -4) factors as (x -2)(x +2). You will note that one of these factors is the same as the denominator in the other fraction.

It looks like you want to simplify ...

$\dfrac{\left(\dfrac{2}{x-2}-\dfrac{3}{x^2-4}\right)}{\left(\dfrac{5}{x^2-4}-\dfrac{2}{x+2}\right)}=\dfrac{\left(\dfrac{2(x+2)}{(x-2)(x+2)}-\dfrac{3}{(x-2)(x+2)}\right)}{\left(\dfrac{5}{(x-2)(x+2)}-\dfrac{2(x-2)}{(x-2)(x+2)}\right)}\\\\=\dfrac{2(x+2)-3}{5-2(x-2)}=\boxed{\dfrac{2x+1}{9-2x}}$

3 0

3 years ago

What is the 6th term of the sequence?<br> an= -3 • 2^n+1

gavmur [86]

Answer:

Step-by-step explanation:

the 6th term of the sequence

an= -3 • 2^n+1 is : a6 = -3.2^7 = - 384

6 0

4 years ago

Jameel Alharbi deposited $1,500 in a savings account that earns 5% compounded quarterly. He made no other deposits or withdrawal

Vikki [24]

Answer:

The amount in the account at the end of the 2nd quarter is $1537.73 ⇒ 2nd answer

Step-by-step explanation:

* Lets revise the compound interest

- Compound interest can be calculated using the formula

A = P (1 + r/n)^(nt)

Where:

• A = the future value of the investment, including interest

• P = the principal investment amount (the initial amount)

• r = the annual interest rate (decimal)

• n = the number of times that interest is compounded per unit t

• t = the time the money is invested for

* Now lets solve the problem

# P = $1500

# r = 5/100 = 0.05

# n = 4 ⇒ quarterly compound

# t = 1/2 ⇒ two quarters means 1/2 year

∴ A = 1500(1 + 0.05/4)^(4 × 1/2) = $1537.73

* The amount in the account at the end of the 2nd quarter is $1537.73

3 0

4 years ago