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Vlad [161]
4 years ago
15

Find the product. tell which strategy you used. 4X6x50

Mathematics
1 answer:
malfutka [58]4 years ago
8 0
4 = 2*2 
(2*50)* (2*6) = 100 * 12=1200

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You have to simplify it <br> -2x+3-(5-6x)
UkoKoshka [18]

Answer: 4x−2

Step-by-step explanation:

-2x+3-(5-6x) remove the parentheses

-2x+3-5+6x collect like terms

(−2x+6x)+(3−5) simplify to get 4x−2

Hope this helps, have a blessed and wonderful day! :-)

- Cutiepatutie

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How do you define each step of this -3(y+3)=2y+3
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Camila has x quarters and y dimes. She has no less than 20 coins worth no more
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3 years ago
Mr. Dixon is ordering pizzas and breadsticks for a school pizza party and has a budget of $76,
sladkih [1.3K]
10x+13y=76 is the awnser
5 0
3 years ago
Find the projection of u = &lt;–6, –7&gt; onto v = &lt;1, 1&gt; a. &lt;-13/2,-13/2&gt; b. &lt;39,91/2&gt; c. &lt;-13/1764,-13/17
Alexandra [31]
<h2>Answer:</h2>

a. <-13/2,-13/2>

<h2>Step-by-step explanation:</h2>

The projection of a vector u onto another vector v is given by;

proj_vu = (\frac{u.v}{|v|^2})v               ----------------(i)

Where;

u.v is the dot product of vectors u and v

|v| is the magnitude of vector v

Given:

u = <-6, -7>

v = <1, 1>

These can be re-written in unit vector notation as;

u = -6i -7j

v = i + j

<em>Now;</em>

<em>Let's find the following</em>

(i) u . v

u . v = (-6i - 7j) . (i + j)

u . v = (-6i) (1i) + (-7j)(1j)          [Remember that, i.i = j.j = 1]

u . v = -6 -7 = -13

(ii) |v|

|v| = \sqrt{(1)^2 + (1)^2}

|v| = \sqrt{2}

<em>Substitute these values into equation (i) as follows;</em>

proj_vu = [\frac{-13}{(\sqrt{2}) ^2}][i + j]

proj_vu = \frac{-13}{2} [i + j]

This can be re-written as;

proj_vu = \frac{-13}{2}i + \frac{-13}{2}j

proj_vu =

5 0
3 years ago
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