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KatRina [158]
3 years ago
11

Find the solutions to the equation -5/2x+3/4x=-3\4

Mathematics
2 answers:
Verizon [17]3 years ago
6 0
-5/2x + 3/4x = -3/4

Multiply everything by 4x

2 × -5 +3 = -3x
-3x = -7
x = 7/3

SSSSS [86.1K]3 years ago
3 0

Simplify both sides of the equation

-5/2 x +3/4 x = -3/4

Combine like terms

(-5/2 x + 3/4 x )

-7/4 x = -3/4

-7/4 x = -3/4

Multiply both sides by 4/(-7)

(4/-7)*(-7/4 x ) = (4/-7 ) * ( -3/4 )

x = 3/7


I hope that's help !

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A hypothesis test is conducted with a significance level of 10%. The alternative hypothesis states that more than 15% of a popul
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D. We cannot conclude that more than 15% of the population has at least one sibling.

Step-by-step explanation:

Data given and notation

n represent the random sample taken

X represent the number of people who has at least one sibling

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\alpha=0.1 represent the significance level

Confidence=90% or 0.90

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion of people who has at least one sibling is more than 0.15:  

Null hypothesis:p\leq 0.15  

Alternative hypothesis:p > 0.15  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Let's assume that the calculated value for this case is z_{calc}

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.1. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(z> z_{calc})=0.27  

So the p value obtained was a very high value and using the significance level given \alpha=0.1 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 10% of significance the proportion of people who has at least one sibling is not significanlty higher than 0.15.

So then the best answer for this case would be:

D. We cannot conclude that more than 15% of the population has at least one sibling.

6 0
3 years ago
F (x) = 13<img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D" id="TexFormula1" title="\sqrt[3]{x}" alt="\sqrt[3]{x}" align=
irga5000 [103]

Answer:

f =

x = 13 = x

k = x

p = x

Step-by-step explanation:

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