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Harman [31]
3 years ago
7

What is the name of the place value of 9 in 199

Mathematics
2 answers:
Sliva [168]3 years ago
8 0

The name of place value of 9 in 199 is ones.

The second 9 has a value of tens.

The number 1 has a place value of hundreds.

coldgirl [10]3 years ago
6 0

The middle number value is Ten the one to the right of it value is One

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Solve for x:<br> 4x – 7 = 8x + 33
Lera25 [3.4K]

Answer:

x = 10

Step-by-step explanation:

Hey there!

To solve this question we will use PEMDAS (order of operations)

4x−7=8x+33

Subtract 8x from both sides.

4x−7−8x=33

Combine 4x and −8x to get −4x.

−4x−7=33

Add 7 to both sides.

−4x=33+7

Add 33 and 7 to get 40.

−4x=40

Divide both sides by −4.

x= 40/-4

Divide 40 by −4 to get −10.

x=−10

6 0
2 years ago
Please help ASAP
belka [17]

Answer:

Option B is correct

Step-by-step explanation:

Hope that helped u

6 0
3 years ago
When a data set is normally distributed, about how much of the data fall within one standard deviation of the mean?
Bezzdna [24]

That would be 68%   answer

6 0
3 years ago
The ratio of the measures of the angles of a triangle is 3:4:8 what are the measures of the angles?
evablogger [386]

Answer:

36 and 48 and 96

Step-by-step explanation:

add 3+4+8=15

all of the angles in a triangle have to add up to 180

so 180÷15=12

now for this ratio, each part will equal 12

so we have to multiply each of the parts by 12

3×12=36

4×12=48

8×12=96

those are the measures of the angles

you can add them up again and see that they equal 180

you can try dividing and you will see that they also equal the ratio

5 0
3 years ago
Jim wants to build a rectangular parking lot along a busy street but only has 2400 feet of fencing available. if no fencing is r
PSYCHO15rus [73]
<span>Length = 1200, width = 600
   First, let's create an equation for the area based upon the length. Since we have a total of 2400 feet of fence and only need to fence three sides of the region, we can define the width based upon the length as: W = (2400 - L)/2
   And area is: A = LW
    Substitute the equation for width, giving: A = LW A = L(2400 - L)/2
    And expand: A = (2400L - L^2)/2 A = 1200L - (1/2)L^2
    Now the easiest way of solving for the maximum area is to calculate the first derivative of the expression above, and solve for where it's value is 0. But since this is supposedly a high school problem, and the expression we have is a simple quadratic equation, we can solve it without using any calculus. Let's first use the quadratic formula with A=-1/2, B=1200, and C=0 and get the 2 roots which are 0 and 2400. Then we'll pick a point midway between those two which is (0 + 2400)/2 = 1200. And that should be your answer. But let's verify that by using the value (1200+e) and expand the equation to see what happens:
   A = 1200L - (1/2)L^2
 A = 1200(1200+e) - (1/2)(1200+e)^2
 A = 1440000+1200e - (1/2)(1440000 + 2400e + e^2)
 A = 1440000+1200e - (720000 + 1200e + (1/2)e^2)
 A = 1440000+1200e - 720000 - 1200e - (1/2)e^2
 A = 720000 - (1/2)e^2
   And notice that the only e terms is -(1/2)e^2. ANY non-zero value of e will cause this term to be non-zero and negative meaning that the total area will be reduced. Therefore the value of 1200 for the length is the best possible length that will get the maximum possible area.</span>
7 0
3 years ago
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