What is the value of this expression 1/3-5

Find the area of the shape, show work pls ill give brainiest

andre [41]

Answer:

6.2

Step-by-step explanation:

Although there's multiple ways to solve this problem, my method will be to simply find the area for the full triangle (the empty + orange triangles) and subtract the area of the smaller, empty triangle.

Now, you that area for a triangle is 1/2*base*height.

To find the measurements for the full triangle, you must add up the bases for the two smaller triangles:

$Base_{total} = Base_{empty} + Base_{orange} \\Base_{total} = 1.9ft + 3.1 ft\\Base_{total} = 5 ft$

Height is the same for both triangles so Height total = 4 ft.

Now the total area can be calculated:

Area total= 1/2* base_total * height_total

Area total = 1/2 * 5ft * 4 ft

Area total = 20 / 2 = 10 ft squared

Lastly, subtract the area of the empty triangle from the total triangle to find the orange triangle.

Area Empty Triangle = 1/2 * base_empty * height_empty

Area Empty Triangle = 1/2 * 1.9ft * 4 ft = 7.6 ft / 2 = 3.8 ft squared

Area total - Area empty = 10ft^2 - 3.8ft^2 = 6.2 ft squared

8 0

3 years ago

Somebody please help me with this !!!

Damm [24]

Step-by-step explanation:

Case 1 :

$3x + 2y = 6 \\ 4x + y = 2 \\ 3x = 6 - 2y \\ x = \frac{6 - 2y}{3} = \\ x = 2 - \frac{2y}{3} \\ 4(2 - \frac{2y}{3} ) + y = 2 \\ 8 - \frac{8y}{3} + y = 2 \\ - 1.67y = - 6 \\$

$y = 3.59 \\ x = 2 - \frac{2y}{3} \\x = 2 - \frac{2 \times 3.59}{3} \\ \\ x = - 0.39$

Case 2 :

$3x + 2y = 6 \\ 4x - y = 2 \\ x = 2 - \frac{2y}{3} \\ 4(2 - \frac{2y}{3} ) - y = 2 \\ 8 - \frac{8y}{3} - y = 2 \\ - 3.67y= - 6 \\ y = 1.63$

$x = 2 - \frac{2y}{3} \\ x = 2 - \frac{2 \times 1.63}{3} \\ x = 2 - 1.087 \\ x = 0.913$

7 0

3 years ago

Negative seven plus four

gulaghasi [49]

Answer:

-3

Step-by-step explanation:

it like 7-4 but then you change the sign to negative since you chance it earlier.

8 0

3 years ago

which expressions are equivalent to the first one? I don't understand how to determine that so please explain. Thanks!

coldgirl [10]

9514 1404 393

Answer:

(a) -(x+7)/y

(b) (x+7)/-y

Step-by-step explanation:

There are several ways you can show expressions are equivalent. Perhaps the easiest and best is to put them in the same form. For an expression such as this, I prefer the form of answer (a), where the minus sign is factored out and the numerator and denominator have positive coefficients.

The given expression with -1 factored out is ...

$\dfrac{-x-7}{y}=\dfrac{1(x+7)}{y}=\boxed{-\dfrac{x+7}{y}} \quad\text{matches A}$

Likewise, the expression of (b) with the minus sign factored out is ...

$\dfrac{x+7}{-y}=\boxed{-\dfrac{x+7}{y}}$

On the other hand, simplifying expression (c) gives something different.

$\dfrac{-x-7}{-y}=\dfrac{-(x+7)}{-(y)}=\dfrac{x+7}{y} \qquad\text{opposite the given expression}$

__

Another way you can write the expression is term-by-term with the terms in alpha-numeric sequence (so they're more easily compared).

Given: (-x-7)/y = (-x/y) +(-7/y)

(a) -(x+7)/y = (-x/y) +(-7/y)

(b) (x+7)/(-y) = (-x/y) +(-7/y)

(c) (-x-7)/(-y) = (x/y) +(7/y) . . . . not the same.

__

Of course, you need to know the use of the distributive property and the rules of signs.

a(b+c) = ab +ac

-a/b = a/(-b) = -(a/b)

-a/(-b) = a/b

__

<u>Summary</u>: The given expression matches (a) and (b).

_____

<em>Additional comments</em>

Sometimes, when I'm really stuck trying to see if two expressions are equal, I subtract one from the other. If the difference is zero, then I know they are the same. Looking at (b), we could compute ...

$\left(\dfrac{-x-7}{y}\right)-\left(\dfrac{x+7}{-y}\right)=\dfrac{-y(-x-7)-y(x+7)}{-y^2}\\\\=\dfrac{xy+7y-xy-7y}{-y^2}=\dfrac{0}{-y^2}=0$

Yet another way to check is to substitute numbers for the variables. It is a good idea to use (at least) one more set of numbers than there are variables, just to make sure you didn't accidentally find a solution where the expressions happen to be equal. We can use (x, y) = (1, 2), (2, 3), and (3, 5) for example.

The given expression evaluates to (-1-7)/2 = -4, (-2-7)/3 = -3, and (-3-7)/5 = -2.

(a) evaluates to -(1+7)/2 = -4, -(2+7)/3 = -3, -(3+7)/5 = -2, same as given

(b) evaluates to (1+7)/-2 = -4, (2+7)/-3 = -3, (3+7)/-5 = -2, same as given

(c) evaluates to (-1-7)/-2 = 4, different from given

3 0

3 years ago

Please help me with this please help!

Basile [38]

Answersharaddhagupta become my friend

3 0

3 years ago