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seraphim [82]
3 years ago
8

What is the multiplicative rate of change for the exponential function f(x) = 2()–x?

Mathematics
1 answer:
quester [9]3 years ago
6 0

Answer:

f(x)-2x=0

Step-by-step explanation:

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What is the range of possible lengths for the third side of a triangle that has side lengths of 7 and 10? WRITER ន I O
stira [4]

Answer:

3 < x < 17

Step-by-step explanation:

triangle inequality theorem: the sum of any two sides must be greater than the third

7 + 10 > x;  x < 17

7 + x > 10;  x > 3

3 0
3 years ago
Name a career in which one would have to use the phythagorean theorem.Give an example of when and how it would be used.Please wr
DanielleElmas [232]

Answer:

The careers that use Pythagoras theorem are mentioned below.

Step-by-step explanation:

The Pythagoras theorem states that the sum of squares of the two sides of right angled triangle is equal to the square of the length of the hypotenuse.

Let a, b and c be the sides of a right triangle where c is the length of the hypotenuse.Then

a^{2}+b^{2}=c^{2}

Pythagoras theorem is used in daily life situations.

A surveyor looks through a telescope toward a measuring stick a fixed distance away, so that the telescope's line of sight and the measuring stick form a right angle.

It is also used to calculate the steepness of slopes and mountains.

8 0
3 years ago
which of the three sets could not be the lengths of the sides of a triangle {6,10,12} {5,7,10} {4,4,9} {2,3,3}
Phoenix [80]

So for this, we will be applying the Triangle Inequality Theorem, which states that the sum of 2 sides must be greater than the third side for it to be a triangle. If any inequality turns out to be false, then the set cannot be a triangle.

A+B>C\\A+C>B\\B+C>A

<h2>First Option: {6, 10, 12}</h2>

Let A = 6, B = 10, and C = 12:

6+10>12\\16>12\ \textsf{true}\\\\6+12>10\\18>10\ \textsf{true}\\\\12+10>6\\22>6\ \textsf{true}

<h2>Second Option: {5, 7, 10}</h2>

Let A = 5, B = 7, and C = 10

5+7>10\\12>10\ \textsf{true}\\\\5+10>7\\15>7\ \textsf{true}\\\\10+7>5\\17>5\ \textsf{true}

<h2>Third Option: {4, 4, 9}</h2>

Let A = 4, B = 4, and C = 9

4+4>9\\8>9\ \textsf{false}\\\\4+9>4\\13>4\ \textsf{true}\\\\4+9>4\\13>4\ \textsf{true}

<h2>Fourth Option: {2, 3, 3}</h2>

Let A = 2, B = 3, and C = 3

2+3>3\\5>3\ \textsf{true}\\\\2+3>3\\5>3\ \textsf{true}\\\\3+3>2\\6>2\ \textsf{true}

<h2>Conclusion:</h2>

Since the third option had an inequality that was false, <u>the third option cannot be a triangle.</u>

5 0
3 years ago
Read 2 more answers
What are the solutions to (x+7)^2=81
Kamila [148]

(x+7)^2=81\iff x+7=\pm\sqrt{81}\\\\x+7=-9\ \vee\ x+7=9\qquad\text{subtract 7 from both sides}\\\\\boxed{x=-16\ \vee\ x=2}

6 0
4 years ago
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Split 15 into the ratio 3:2
morpeh [17]

Answer:

Step-by-step explanation:

8 0
3 years ago
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