Ask question

Ask question

All categories

lisabon 2012 [21]

3 years ago

15

A multiparous client thought to be at 14 weeks' gestation based on uterine size has such severe morning sickness that she has "n

ot been able to keep anything down for a week." the nurse should review the results of the urinalysis for:

1 answer:

beks73 [17]3 years ago

7 0

idk if you want a long answer, but its ketones

You might be interested in

Elijah, a 17-year-old high school junior, is an integral part of the school soccer team. He is a good vocal artist and is part o

Svetradugi [14.3K]

Answer: Identity moratorium

Explanation:

Identity moratorium is the third identity status in Marcias theory. This identity represents a high exploration of different things or skill but low commitment to all of them. This is stage of identity crisis in youth. They have tried out different things but are not yet certain of a career type.

6 0

4 years ago

Bacterial DNA is circular and arrayed in a region of the cell known as what? Answers: nucleus, nuceloid, mitochondria, Golgi app

Oksi-84 [34.3K]

I believe the answer is nuceloid

6 0

3 years ago

Read 2 more answers

What is most likely cause of the change in population size in year 6 shown in the graph below

Harman [31]

I think your answer is a hot summer. during this phase, there would be rapid growth in vegetation leading to increased population in rabbits and other rodents...

7 0

3 years ago

Snails and shell fish are grouped as

Tanzania [10]

Molluscs. hope this helps!

8 0

3 years ago

Read 2 more answers

Black fur (B) is dominant to white fur (b) in guinea pigs. An F1 cross was conducted and resulted in 100% heterozygous guinea pi

Lemur [1.5K]

Answer:

D. 1 BB : 2 Bb : 1 bb

Explanation:

This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.

If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:

Bb = B and b

Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:

1 BB : 2 Bb : 1 bb

BB and Bb = black fur guinea pigs

bb = white fur guinea pigs

3 0

3 years ago