If something cost 39.99 and it's 10% off how much would it cost

PLEASE look at the photo of my computer to see the problem

antoniya [11.8K]

Answer:

the answer is 2+2i√3

Step-by-step explanation:

hope this helps

7 0

3 years ago

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A path of a toy rocket thrown upward from the ground at a rate of 208 ft/sec is modeled by the quadratic function h(t) = -16t +2

skelet666 [1.2K]

Answer:

The time = 6.5 seconds and the maximum height reached by the rocket = 676 feet

Step-by-step explanation:

A path of a toy rocket thrown upward from the ground at a rate of 208 ft/sec is modeled by the quadratic function h(t) = -16 $t^{2}$ +208t.

We have to find when the rocket will reach its maximum height.

When the rocket reaches its maximum height, $\frac{dh}{dt}$ = 0.

h(t) = -16 $t^{2}$ +208t

$\frac{dh}{dt}$ = - 32t + 208 = 0

t = 6.5 seconds

At t = 6.5 seconds it is at maximum height.

Maximum height = - 16 $\times (6.5^{2} ) + 208\times 6.5$

= 676 feet

3 0

4 years ago

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Determine the vertex of the function f(x) = 2(x - 5)2 + 8.

Pachacha [2.7K]

Solve for x, which can be done by moving x to the other side.
2(x-5)^2+8

So, x = 5

The y value is the number at the end and we can see that it is positive 8.

y = 8

Write it out as a coordinate pair and you would get (5,8) or answer choice D

8 0

4 years ago

solve the problem related to population growth.A city had a population of 23,900 in 2007 and a population of 25,100 in 2012.(a)

Finger [1]

Solution

a)

To find the exponential growth function, we apply the exponential growth formula which is

$N(t)=a(1+k)^t$

Where

$\begin{gathered} a\text{ is the }initial\text{ population} \\ k\text{ is the growth rate} \\ t\text{ is the number of time intervals} \end{gathered}$

Given that

$\begin{gathered} a=23,900 \\ N(5)=25,100 \\ t=2012-2007=5 \end{gathered}$

Substitute the variables into the exponential growth formula

$\begin{gathered} 25100=23900(1+k)^5 \\ \text{Divide both sides by 23,900} \\ \frac{25100}{23900}=\frac{23900(1+k)^5}{23900} \\ 1.05021=(1+k)^5^{} \\ \sqrt[5]{1.05021}=1+k \\ 1.00984=1+k \\ \text{Collect like terms} \\ k=1.00984-1 \\ k=0.00984 \end{gathered}$

Hence, the exponential growth function is