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artcher [175]
4 years ago
13

Answer choices are 67, 55, 43, and 12.

Mathematics
1 answer:
olasank [31]4 years ago
4 0

Answer:

43

Step-by-step explanation:

If BD bisects the angle, then the two angles it creates  are equal

55 = x+12

Subtract 12 from each side

55-12 = x+12-12

43 =x

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-2 1/4 ÷ (-3 1/3) =<br><br> I will give brainliest
Vanyuwa [196]

Answer:

-2.09375

Step-by-step explanation:

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4 years ago
What is the area of the figure below?<br> 4 ft<br> 61<br> 5 ft<br> 13 ft<br> 4 ft
meriva

Answer:

The answer would be 69.5ft^2

Step-by-step explanation:

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4 years ago
6/16 OR 30/80 WHICH ONE is bigger?
spin [16.1K]

There's two possible ways to find the answer to this.  First you can find a common denominator to reduce both to.  In this case, they can both reduce to a common denominator of 8.  So 6/16 reduces to 3/8 and 30/80 also reduces to 3/8, so they are equal.  The other way is to use a calculator and turn them into decimals by dividing the numerator by the denominator.  They both come out to be .375. Once again they are equal.  You can use whichever method is easier for you.
8 0
4 years ago
Read 2 more answers
At a restaurant a manger recorded the sales for one of his servers named
TiliK225 [7]

Answer: b. Damarias median sale is $52

Step-by-step explanation:

Hi, the correct option is b. Damarias median sale is $52.

If we rank the sales order from lowest to highest

28 46 48 48 52 52 59 60 71 192

Since 52 is the middle value, it's the median, because 4 sales are above it and 4 sales are below it.

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8 0
3 years ago
For a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears. Minitab was used
kkurt [141]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Correlation Coefficient (r) = 0.989

alph=0.05

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Yes, there exists a linear relationship between chest size and weight as the value of the correlation Coefficient exceeds the critical value.

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To determine the the proportion of variation in weight that can be explained by the linear regression line between weight and chest size, we need to obtain the Coefficient of determination(r^2) of the model.

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r^2 = 0.989^2 = 0.978121

Hence, about 0.978 (97.8%) of the variation in weight can be explained by the linear relationship between weight and chest size.

4 0
4 years ago
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