Question

Solve for y. 2y^2+5y+63=(y+7)^2

Answer 1

Answer: y = 2 or 7

Step-by-step explanation:Copy and open the bracket

2y² + 5y +63 = (y + 7 )²

expand the right hand expression (y + 7 )², which now becomes

y² + 14y +49 , now equate the 2 together and arrange it into a quadratic structure

2y² + 5y +63 = y² + 14y + 49

2y² - y² + 5y - 14y +63 - 49 = 0

y² -9y + 14 = 0

Now, factorize the expression using grouping or any method

y² -7y - 2y + 14 = 0, considering two factors, when multiplied together gives +14, and when added together gives - 9

Considering the common factors ,it now becomes

y( y - 7) -2(y - 7) =0

(y - 2)(y - 7) = 0

To find the root of y,

when y - 7 = 0

y = 7, and when y- 2 =0, y = 2

Therefore, the solution of the equation is

y = 2, or 7.