Problem 1
<h3>Answers:</h3><h3>angle 6 = 50</h3><h3>angle 7 = 50</h3><h3>angle 8 = 40</h3>
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Work Shown:
point E = intersection point of diagonals.
x = measure of angle 6
y = measure of angle 8
angle 7 is also x because triangle AED is isosceles (AE = ED)
Focus on triangle AED, the three angles A, E, D add to 180
A+E+D = 180
x+80+x = 180
2x+80 = 180
2x = 180-80
2x = 100
x = 100/2
x = 50
So both angles 6 and 7 are 50 degrees.
Turn to angle 8. This is adjacent to angle 7. The two angles form a 90 degree angle at point A. This is because a rectangle has 4 right angles.
(angle7)+(angle8) = 90
50+y = 90
y = 90-50
y = 40
angle 8 = 40 degrees
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Problem 2
<h3>Answers:</h3><h3>angle 2 = 61</h3><h3>angle 3 = 61</h3>
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Work Shown:
Angle 5 is 29 degrees (given). So is angle 4 because these are the base angles of isosceles triangle DEC (segment DE = segment EC)
angle 3 and angle 4 form a 90 degree angle
x = measure of angle 3
(angle 3)+(angle 4) = 90
x+29 = 90
x = 90-29
x = 61
Angle 2 is congruent to angle 3 since triangle BEC is isosceles (BE = EC), so both angle 2 and angle 3 are 61 degrees each.
Answer:
Step-by-step explanation:
In my opinion, I beleive it's y=9 becasue the rest of the equations have x in them. bth, this is me just by looking at the equation.
Remember that the y-intercept is where the function has a value of 
and the x-intercept is where the function has a value of 
. Thus, to find the x-intercept and y-intercept, we can substitute these values into the equation and solve for the other variable.
<u>x-intercept</u>
Since the x-intecept has a y-value of 0, we can substitute this into the function and solve for 
.
The x-value of the x-intercept is 
and the y-value is 0, meaning that the x-intercept has coordinates 
.
<u>y-intercept</u>
Since the y-intercept has a x-value of 0, we can substitute this into the equation and solve for 
:
The y-value of the y-intercept is -3, meaning that the y-intercept of the function is 
.
Answer:
It is the first bubble.
Step-by-step explanation:
multiply the fraction 
multiply the numerators and denominators seperatly
calculate the product
multiply the numbers
solution
