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Alenkasestr [34]
3 years ago
9

Write a single Java if-else statement that outputs the value of a char variable GRADE if GRADE is equal to 'A' or 'B' or 'C' or

'D' or 'F'; otherwise, output the message "Input Error".
Computers and Technology
1 answer:
ad-work [718]3 years ago
3 0

Answer:

Following are the program in java is given below

import java.util.*; // import package

public class Main // main class

{

public static void main(String[] args) // MAIN FUNCTION

{

Scanner scan2 = new Scanner(System.in);// scanner CLASS

System.out.println("Enter the Grade ");

char GRADE = scan2.next().charAt(0);//Read input by user

if(GRADE=='A' || GRADE=='B' || GRADE=='C' || GRADE=='D' || GRADE=='F' ) // //CHECK CONDITION

{    

System.out.println("The GRADE is :" +GRADE); // display grade  

}

else // Else block

{

System.out.println(" Input Error"); // display message

}

}

}

Output:

Enter the Grade

D

The GRADE is :D

Explanation:

Following are the description of program

  • Create the object of scanner class for read the value of grade by the user .
  • Read the value of "GRADE" variable by using the scanner class object  scan 2
  • Now check the condition in if block if the "GRADE" is  'A' or 'B' or 'C' or 'D' or 'F' then display the value of the GRADE variable otherwise else block is executed and input error message is displayed .

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Explanation:

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Consider the following high-level recursive procedure: long long int flong long int n, long long int k long long int b b k+2; if
Stolb23 [73]

Answer:

f(long long, long long):

push rbp

mov rbp, rsp

push rbx

sub rsp, 40

mov QWORD PTR [rbp-40], rdi

mov QWORD PTR [rbp-48], rsi

mov rax, QWORD PTR [rbp-48]

add rax, 2

mov QWORD PTR [rbp-24], rax

cmp QWORD PTR [rbp-40], 0

jne .L2

mov QWORD PTR [rbp-24], 8

jmp .L3

.L2:

mov rax, QWORD PTR [rbp-40]

lea rdx, [0+rax*4]

mov rax, QWORD PTR [rbp-24]

lea rbx, [rdx+rax]

mov rax, QWORD PTR [rbp-48]

lea rdx, [rax+1]

mov rax, QWORD PTR [rbp-40]

sub rax, 1

mov rsi, rdx

mov rdi, rax

call f(long long, long long)

add rax, rbx

mov QWORD PTR [rbp-24], rax

.L3:

mov rdx, QWORD PTR [rbp-24]

mov rax, QWORD PTR [rbp-48]

add rax, rdx

add rsp, 40

pop rbx

pop rbp

ret

Explanation:

8 0
3 years ago
Given an int variable n that has been initialized to a positive value and, in addition, int variables k and total that have alre
Fudgin [204]

Answer:

The c++ program to implement the while loop is given below.

#include <iostream>

using namespace std;

int main() {

  // declaration of integer variables

   int k, n, total;

   // initialization of integer variables

   k=1, n=4, total=0;

//  loop executed till value of k becomes equal to value of n

   while( k <= n ){

       // cube of every integer is added to the variable total

       total = total + ( k * k * k );

       // value of k is incremented to go to the next number

k = k + 1 ;

   }  

   return 0;

}  

Explanation:

The program begins with the declaration of integer variables.  

int k, n, total;

This is followed by initialization of these variables.

k=1, n=4, total=0;

The while loop runs over the variable k which is initialized to 1. The loop runs till value of k reaches the value of integer n.

First, cube of k is computed and added to the variable total.

After first execution of the loop, total is initialized to the cube of 1.

Next, value of variable k is incremented by 1 so that k is initialized to next integer.

After first execution of the loop, k is incremented from 1 to 2.

while( k <= n )

{

total = total + ( k * k * k );

k = k + 1 ;

   }

When the value of k reaches the value of integer n, the cube of n is calculated and added to the variable, total.

When k is incremented, it becomes more than n and hence, loop gets terminated.

As the return type of main is int, the program terminates with the statement shown below.

return 0;

No output is displayed as it is not mentioned in the question.

No user input is taken as it is mentioned that integer variables are already initialized.

4 0
3 years ago
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