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Alecsey [184]
3 years ago
12

1. Find m2K.

Mathematics
1 answer:
Kruka [31]3 years ago
5 0

Answer:

m∠k = 60°

Step-by-step explanation:

  • an exterior angle of a triangle is equal to the sum of the opposite interior angles

4x + 2 + 6x - 12 = 130

to find x:

4x + 2 + 6x - 12 = 130

4x + 6x = 130 - 2 + 12

10x = 120

x = 120/10

x = 12

apply the value of x to find the measure of angle K:

k = 6*12 - 12 = 60

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How many dots are in the 4th step
Sever21 [200]

Answer:

24

Step-by-step explanation:

if we observe carefully we can see that the difference in the number of dots from the first picture to the second picture is 5

and the difference in the number of dots from the second picture to the third picture is 7

so there might be a chance that the difference between the 3rd figure and 4th figure may be 9

so my answer is the number of dots in the 3rd picture + 9

15+9= 24

3 0
2 years ago
Compute the slope of the line below. Enter your answer as a fraction or
Arada [10]

Answer:

  1. yirsurusitr

Step-by-step explanation:

f

  1. fftzethatwtk
  2. dg5teyd5lwey Hrhht c.f.rsxtmrshzt fsfyrscytn

5 0
2 years ago
Which is the expanded form of 124,750,000?
frez [133]

Answer: The correct answer is B.

Step-by-step explanation:

100,000,000 + 20,000,000 + 4,000,000 + 700,000 + 50,000 = 124,750,000

7 0
3 years ago
Read 2 more answers
◆ Quadratic Equations ◆<br>Please help !
Mila [183]
I'm sure there's an easier way of solving it than the way I did, but I'm not sure what it could be. Never dealt with a problem like this before.

Anyway, I just plugged in and tested. Chose random values for a, b, c, and d, which follow the rule 0 < a < b < c < d:

a = 1
b = 2
c = 3
d = 4

\sf ax^2+(1-a(b+c))x+abc-d)

\sf 1x^2+(1-1(2+3))x+(1)(2)(3)-(4))

Simplify into standard form:

\sf x^2+(1-1(5))x+6-4

\sf x^2+(1-5)x+2

\sf x^2-4x+2

Use the quadratic formula to solve:

\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}

For functions in the form of \sf ax^2+bx+c. So in this case:

a = 1
b = -4
c = 2

Plug them in:

\sf x=\dfrac{4\pm\sqrt{(-4)^2-4(1)(2)}}{2(1)}

Solve for 'x':

\sf x=\dfrac{4\pm\sqrt{16-8}}{2}

\sf x=\dfrac{4\pm\sqrt{8}}{2}

\sf x\approx\dfrac{4\pm 2.83}{2}

\sf x\approx 0.59,3.41

So the answer would be A.
3 0
3 years ago
The mean age of Mr Jasmi,Miss Haslinda and their three children is 38 years. The mean age of their three children is 18 years. C
DedPeter [7]
Answer: 68

Explanation:

Let x be the age of Mr Jasmi
y be the age of Miss Haslinda
a + b + c be the age of the 3 children

We can write:
(x + y + a + b + c)/5 = 38

But:
(a + b + c)/3 = 18
a + b + c = 18(3)
a + b + c = 54

Substitute this value to our first equation

(x + y + 54)/5 = 38
x + y + 54 = 38(5)
x + y + 54 = 190
x + y = 190 - 54
x + y = 136

Thus:
Mean age of (mr jasmi and miss Linda) = (x+y)/2

But x + y = 136

=> mean age = 136/2 = 68
4 0
2 years ago
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