Answer:
Step-by-step explanation:
Factor 6f3−8f2+20−15f
6f^3−8f^3−15f
=(3f−4)(2f2−5)
Answer:
(3f−4)(2f^2−5)
Find the group you want to factor, such as in the first parenthesis, you remove 3f from the whole equation, and end up with 3f-4. You take the end value, and group it with -5. You will then end up with 2f^2 -5.
Hope this Helps!
Answer:
- a) (0,0), (-4, 1), (-1,2)
- b) None
Step-by-step explanation:
- <em>There are two ways of solving similar problems. One- substitute x and y with respective coordinates and verify if the inequalities are correct. Two- graph the lines and see if the points are in the intersection zones.</em>
- <em>We'll go with the first method. </em>
- <em>Remember both inequalities should be correct for the same point to accept it as a solution.</em>
<u>Given points </u>
<h3>a) <u>The system of inequalities</u></h3>
<u>Point (0,0)</u>
- 0 > 0 - 1 = -1 correct
- 0 < -1/2(0) + 2 = 2 - correct
- Yes
<u>Point (-4,1)</u>
- 1 > -4 - 1 = -5 - correct
- 1 < -1/2(-4) + 2 = 4 - correct
- Yes
<u>Point (-1,2)</u>
- 2 > -1 - 1= -2 - correct
- 2 < -1/2(-1) + 2 = 2.5 - correct
- Yes
<h3>b) <u>The system of inequalities</u></h3>
<u>Point (0, 0)</u>
- 0 - 2(0) = 0 ≥ 4 - incorrect
- 2(0) - 0 = 0 ≥ -1 - correct
- No
<u>Point (-4, 1)</u>
- -4 - 2(1) = - 6 ≥ 4 - incorrect
- 2(-4) - 1 = - 9 ≥ -1 - correct
- No
<u>Point (-1,2)</u>
- -1 - 2(2) = -5 ≥ 4 - incorrect
- 2(-1) - 2 = - 4 ≥ -1 - correct
- No
The equation that is true is A
