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Mrac [35]
3 years ago
9

Read the numbers and decide what the next number should be. 20 30 40 50 60 70

Mathematics
2 answers:
Lerok [7]3 years ago
6 0
They are asking for pattern recognition of a sequence of numbers. If you follow the pattern the next logical number will be 80
goldenfox [79]3 years ago
4 0
80 Because the numbers are going up by 10

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What is the full answer to pie
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Answer:

\pi= 3.1415926...= c/d

Step-by-step explanation

Pie is infinite so there is no simple answer.

circumference divided by the diameter = pie

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Solve for the measure of c. Round decimals to the nearest tenth.
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Do you know the answer to this mate ?

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Describe a situation that 14-3xP could represent
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Represent what you have to be more specific


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Can someone help me with this answer I’m on a test and it’s almost due
Brrunno [24]

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6 0
3 years ago
According to DeMorgan 's theorem, the complement of W · X + Y · Z is W' + X' · Y' + Z'. Yet both functions are 1 for WXYZ = 1110
sergeinik [125]

Answer:

The parenthesis need to be kept intact while applying the DeMorgan's theorem on the original equation to find the compliment because otherwise it will introduce an error in the answer.

Step-by-step explanation:

According to DeMorgan's Theorem:

(W.X + Y.Z)'

(W.X)' . (Y.Z)'

(W'+X') . (Y' + Z')

Note that it is important to keep the parenthesis intact while applying the DeMorgan's theorem.

For the original function:

(W . X + Y . Z)'

= (1 . 1 + 1 . 0)

= (1 + 0) = 1

For the compliment:

(W' + X') . (Y' + Z')

=(1' + 1') . (1' + 0')

=(0 + 0) . (0 + 1)

=0 . 1 = 0

Both functions are not 1 for the same input if we solve while keeping the parenthesis intact because that allows us to solve the operation inside the parenthesis first and then move on to the operator outside it.

Without the parenthesis the compliment equation looks like this:

W' + X' . Y' + Z'

1' + 1' . 1' + 0'

0 + 0 . 0 + 1

Here, the 'AND' operation will be considered first before the 'OR', resulting in 1 as the final answer.

Therefore, it is important to keep the parenthesis intact while applying DeMorgan's Theorem on the original equation or else it would produce an erroneous result.

3 0
3 years ago
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