Answer:
Step-by-step explanation:
Given the coordinate points (6, -3) and (7, -10), we are to find the equation of a line passing through this two points;
The standard equation of a line is y = mx+c
m is the slope
c is the intercept
Get the slope;
m = Δy/Δx = y2-y1/x2-x1
m = -10-(-3)/7-6
m = -10+3/1
m = -7
Get the intercept;
Substitute the point (6, -3) and m = -7 into the expression y = mx+c
-3 = -7(6)+c
-3 = -42 + c
c = -3 + 42
c = 39
Get the required equation by substituting m = -7 and c= 39 into the equation y = mx+c
y = -7x + 39
Hence the required equation is y = -7x + 39
Answer:
B: y=3x+18
Step-by-step explanation:
Answer:
a= 9/4
Step-by-step explanation:
2m^(5/2)/m^(1/4)
2m^(5/2 -1/4)
2m^(9/4)
Hope you find this helpful <3
We have that
using a graph tool--------------> graph the <span> cosecant function
</span>see the attached figure
the answer is the option B
Answer:64.09
Step-by-step explanation:
